C(HClO) = 0,3 M.
<span>V(HClO) = 200 mL = 0,2 L.
n(HClO) = </span>c(HClO) · V(HClO).
n(HClO) = 0,06 mol.<span>
c(KClO</span>) =
0,2 M.
<span>V(KClO) = 0,3 L.
n(KClO) = 0,06 mol.
V(buffer solution) = 0,2 L + 0,3 L = 0,5 L.
ck</span>(HClO) = 0,06 mol ÷ 0,5 L = 0,12 M.
cs(KClO) = 0,06 mol ÷ 0,5 L = 0,12 M.<span>
Ka(HClO</span>) =
2,9·10⁻⁸.<span>
This is buffer solution, so use Henderson–Hasselbalch
equation:
pH = pKa + log(cs</span> ÷ ck).<span>
pH = -log(</span>2,9·10⁻⁸) + log(0,12 M ÷ 0,12 M).<span>
pH = 7,54 + 0.
pH = 7,54</span>
Answer:
4HCl(g) + O₂(g) → 2Cl₂(g) + 2H₂O(g)
Explanation:
In order to find the equation we should state:
The reactants → Hydrogen chloride (HCl) and oxygen (O₂)
The products → Chlorine gas (Cl₂) and water gas (H₂O)
The balanced equation is:
4HCl + O₂ → 2Cl₂ + 2H₂O
It is a redox reaction, where the oxygen reduces to make water, and the chloride is oxidized to produce elemental chlorine.
250 --> 125 --> 62.5 --> 31.25
each arrow equals one half life, so 3 half lives
14 days/ 3 half lives =
4.67 days = half life
<span>B) a cube with a ball stuck on each of its eight corners and one suspended at its center </span>
It’s Thai right? I want to help but don’t know how to answer this question.
