The combustion of hexane (C6H14), a component of gasoline, is represented by the balanced chemical equation: 2 C6H14(l) + 19 O2(g) " 12 CO2(g) + 14 H2O(g). If 1.0 mole of hexane undergoescombustion, moles of O2 are required.
If you want to find density, do mass divided by the volume and there’s your answer!
Their are 18 covalent bonds in a molecule of cyclohexane
17.40 sec is the time will take to smell second perfume after diffusion takes place
Acc. to Graham's law of Diffusion
Diffusion of Gas inversely proportional to square root of its Molecular mass.
<u>rb (Perfume B)</u>
ra(perfume A)
=
its equation (1)
Give molar mass of Perfume A = 275 g/mol
molar mass of Perfume B= 205g/mol putting value in (1)
» 
<em> its eq (2)</em>
» Perfume B will defuse 1:16 times faster than perfume A.
Hence, perfume B will be first smelled by Person.
Sf Equal volume V of two goes diffuse in t1 and t2 sec. respectively ton

Now,, from eq(2) toto
1/1:15 = 
ta
Given tb =the smell of Perfume B as it diffuse faster
ta= 1.15 x 15 see
=ta2=17.40 sec
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Answer:
It's A
Explanation:
It starts as one molecule and splits into two which is the definition of a decomposition reaction