Answer:
What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
Explanation:
The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
Answer:
Energy is inversely proportional to wavelength.
Explanation:
The amount of energy, E, a wave carries is given as:
E = hf
where h = Planck's constant and f = frequency of the wave
Frequency and wavelength are related by the equation:
c = λf
=> f = c/λ
where λ = wavelength
Therefore, energy is:
E = hc/λ
This shows that energy is inversely proportional to wavelength. As wavelength increase, energy decreases and vice versa.
Answer:
a = 5 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.

where:
Vf = final velocity = 20 [m/s]
Vo = initial velocity = 10 [m/s]
t = time = 2 [s]
a = acceleration [m/s²]
Now replacing:
![20 =10 +a*2\\10=2*a\\a=5[m/s^{2} ]](https://tex.z-dn.net/?f=20%20%3D10%20%2Ba%2A2%5C%5C10%3D2%2Aa%5C%5Ca%3D5%5Bm%2Fs%5E%7B2%7D%20%5D)
Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier. It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.
1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .
Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach 3,000,000 m/s ?
(3,000,000 m/s) / (9.8 m/s²) = 306,122 seconds .
(That's 5,102 minutes.)
(That's 85 hours.)
(That's 3.54 days.)
Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s
Distance = (average speed) x (time)
= (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters
= 459 million kilometers
That's like from Earth
to Sun
to Earth
to Sun.
Answer:

Explanation:
Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is
. If we call 1 the situation when the student is at the rim and 2 the situation when the student is at
from the center, then we have:

Or:

And we want to calculate:

The total moment of inertia will be the sum of the moment of intertia of the disk of mass
and radius
, which is
, and the moment of intertia of the student of mass
at position
(which will be
or
) will be
, so we will have:

or:

which for our values is:
