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Svetach [21]
3 years ago
15

On another planet, a marble is released from rest at the top of a high cliff. It falls 4.00 m in the first 1 s of its motion. Th

rough what additional distance does it fall in the next 1 s
Physics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

Distance(h1) = 12 m

Explanation:

Given :

Height of cliff (h) = 4m

Time (t) = 1s

Intial velocity (u) = 0m/s

Computation:

Distance(h) = 1/2(g)(t)²

4 = 1/2(g)

g = 8m/s   ²

Distance(h1) = 1/2(g)[(t1)²-(t)²]

Distance(h1) = 1/2(8)(3)

Distance(h1) = 12 m

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8 0
3 years ago
ASTM A229 oil-tempered carbon steel is used for a helical coil spring. The spring is wound with D = 50 mm d = 10.0 mm, and a pit
horrorfan [7]

Answer

given,

D = 50 mm = 0.05 m

d = 10 mm = 0.01 m

Force to compress the spring

F = \dfrac{d^4G\delta}{8D^3N}

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F = \dfrac{d^4G}{8D^3}\times 0.004

F = \dfrac{0.1^4\times 79\times 10^9}{8\times 0.05^3}\times 0.004

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stress correction factor from stress correction curve is equal to 1.1

now, calculation of corrected stress

\tau = \dfrac{8FDk_s}{\pi d^3}

\tau = \dfrac{8\times 3160 \times 0.05 \times 1.1}{\pi \times 0.01^3}

              = 442.6 Mpa

The tensile strength of the steel material of  ASTM A229 is equal to 1300 Mpa

now,

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\tau_s \leq 0.45 \times 1300

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6 0
3 years ago
Read 2 more answers
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