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Svetach [21]
3 years ago
15

On another planet, a marble is released from rest at the top of a high cliff. It falls 4.00 m in the first 1 s of its motion. Th

rough what additional distance does it fall in the next 1 s
Physics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

Distance(h1) = 12 m

Explanation:

Given :

Height of cliff (h) = 4m

Time (t) = 1s

Intial velocity (u) = 0m/s

Computation:

Distance(h) = 1/2(g)(t)²

4 = 1/2(g)

g = 8m/s   ²

Distance(h1) = 1/2(g)[(t1)²-(t)²]

Distance(h1) = 1/2(8)(3)

Distance(h1) = 12 m

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boyakko [2]

Answer:

because they are found freely in nature uncombined so they are highly reactive with other elements

3 0
3 years ago
Read 2 more answers
A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log float
storchak [24]

Answer:

 t ’= \frac{1450}{0.6499 + 2 v_r},  v_r = 1 m/s       t ’= 547.19 s

Explanation:

This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.

By the time the boat goes up the river

        v_b - v_r = d / t

By the time the boat goes down the river

        v_b + v_r = d '/ t'

let's subtract the equations

       2 v_r = d ’/ t’ - d / t

       d ’/ t’ = 2v_r + d / t

       t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }

In the exercise they tell us

         d = 1.22 +1.45 = 2.67 km= 2.67 10³ m

         d ’= 1.45 km= 1.45 1.³ m

at time t = 69.1 min (60 s / 1min) = 4146 s

the speed of river is v_r

      t ’= \frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \  + 2 \ v_r}

      t ’= \frac{1450}{0.6499 + 2 v_r}

In order to complete the calculation, we must assume a river speed

          v_r = 1 m / s

       

let's calculate

      t ’= \frac{ 1450}{ 0.6499 + 2 \ 1}

      t ’= 547.19 s

8 0
3 years ago
A mixture of 1.00g h2 and 1.00g he is placed in a 1.00l container at 27 celcius calculate the partial pressure of each gas and t
r-ruslan [8.4K]
<span>PV = nRT moles of H2 = 1/2 = 0.5 moles of He = 1/4 =0.25 T = 273 + 27 partial pressure of H2 Px1 = 0.5x0.083x300 P=12.45 atmospheres PP of He px1 = 0.25x0.083x300 P =6 22 atmospheres Totla pressure = 6.22 + 12.45 = 18.68 atm</span>
4 0
3 years ago
Laboratory experiments, observational field studies, and model-building are all examples of different forms of scientific invest
Ne4ueva [31]

Answer:

C

Explanation:

8 0
3 years ago
A round flat metal coil has 180 turns and negligible resistance. It is connected in a series circuit with a 17-Ω resistor, with
evablogger [386]

Answer: C) 0.25 m

Explanation: In order to explain this problem we have to consider the Faraday law, we have:

ε=-dФ/dt where ε the emf induced by the change of the magnetic field given by dФ/dt.

then ε=I*R=17*6=102 V

We have a coil then we have the magnetic flux as follow:

Ф=N*A*B then we have

dФ/dt= N*A*dB/dt  where A and N is the area and number of turn of the coil.

A=π*R^2 where R is the radius of teh coil.

Finally we have;

dФ/dt= N*π*R^2*dB/dt then

R= [dФ/dt/(N*π*dB/dt)]^1/2= [102/(180*π*3)]1/2=245.2*10^-3=≅0.25m

6 0
3 years ago
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