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Svetach [21]
3 years ago
15

On another planet, a marble is released from rest at the top of a high cliff. It falls 4.00 m in the first 1 s of its motion. Th

rough what additional distance does it fall in the next 1 s
Physics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

Distance(h1) = 12 m

Explanation:

Given :

Height of cliff (h) = 4m

Time (t) = 1s

Intial velocity (u) = 0m/s

Computation:

Distance(h) = 1/2(g)(t)²

4 = 1/2(g)

g = 8m/s   ²

Distance(h1) = 1/2(g)[(t1)²-(t)²]

Distance(h1) = 1/2(8)(3)

Distance(h1) = 12 m

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<span>Fnet = m • a</span>

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7 0
3 years ago
The magnitude of the electric current is directly proportional to the _____________ of the electric field.
Harlamova29_29 [7]
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3 years ago
The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample
Bezzdna [24]

Answer:

4589.05 year

Explanation:

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\lambda =\frac{0.693}{5730}=1.2094\times 10^{-4}\ per\ year

So 0.574=e^{-1.2094\times 10^{-4}t}

e^{1.2094\times 10^{-4}t}=\frac{1}{0.574}=1.742

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3 years ago
If an hockeypuck slides on a perfectly frictionless surface it will eventually slow down because of its inertia ?
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3 0
4 years ago
A small sandbag is dropped from rest from a hovering hot-air balloon. (assume the positive direction is upward.) (a) after 1.5 s
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solution:

We know v0 = 0, a = 9.8, t = 4.0. We need to solve for v

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we use the equation:

v = v0 + at

v = 0 + 9.8*4.0

v = 39.2 m/s

Now we just need to solve for d, so we use the equation:

d = v0t + 1/2*a*t^2

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d = 78.4 m

3 0
3 years ago
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