Answer:
not the best but that is alright
Explanation:
how is your day :)
Answer:
209.98 g of NaOH
Explanation:
We are given;
- Volume of HCl as 3 L
- Molarity of HCl as 1.75 M
We are required to calculate the mass of NaOH required to completely neutralize the acid given.
First, we write a balanced equation for the reaction between NaOH and HCl
That is;
NaOH + HCl → NaCl + H₂O
Second, we determine the number of moles of HCl
Number of moles = Molarity × Volume
= 1.75 M × 3 L
= 5.25 moles
Third, we use the mole ratio to determine the moles of NaOH
From the reaction,
1 mole of NaOH reacts with 1 mole of HCl
Therefore;
Moles of NaOH = Moles of HCl
= 5.25 moles
Fourth, we determine the mass of NaOH
Molar mass of NaOH = 39.997 g/mol
Mass of NaOH = 5.25 moles × 39.997 g/mol
= 209.98 g
Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl
The answer is C. condenses
C) Calcium chloride has stronger inter molecular forces than water.
Answer:
Explanation:
The amine functional group is obtained by subsititution of one or more hydrogen atoms in the ammonia compound.
Ammonia is NH₃.
Then,
- by substituting one hydrogen you obtain R - NH₂.
- by substituting two hydrogens you obtain R' - NH - R''
- by subsituting the three hydrogens you obtain:
R'''
|
R' - N - R''
In this case, the three subsitutuents are silyl groups. The silyl group is derived form silane and is SiH₃. So, the tcompound <em>trisilylamine</em> is:
SiH₃
|
SiH₃ - N - SiH₃
Thus, you can count 3 hydrogen atoms for every silylgroup for a total of <u><em>9 hydrogen atoms in each molecule of trisilylamine.</em></u>