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ad-work [718]
3 years ago
13

A barrel of crude oil has a volume of 42 gallons, only approximately 45% of which is processed into gasoline. If your car achiev

es 36 mi/gal, and you drive 36,000 miles in one year, how many barrels of crude oil are required to run your car for a year?
Chemistry
1 answer:
balandron [24]3 years ago
4 0

Answer:

The number of barrels of crude oil required to run the car for a year is 52.9 barrels of crude oil

Explanation:

The information given are as follows;

Percentage of crude oil processed into gasoline = 45%

Distance achieved per gallon by car = 36 mi/gal

Distance driven per year = 36,000 miles

Gasoline\,  usage \,  in \, one \,  year = \dfrac{Distance \  driven\  per \ year }{Distance\  achieved \ per gallon \ by \ car } = \dfrac{36000\, miles}{36\, miles/gallon}\dfrac{36000\, miles}{36\, miles/gallon} = 1000 \, gallons

∴ Gasoline usage in one year = 1,000 gallons

Percentage of crude oil processed into gasoline = 45%

Hence, where 45% of the crude oil produces 1000, the volume of crude, x, from which the gasoline is sourced becomes;

x × 45/100 = 1000 gallons

x =100 × 1000/45 = 20000/9 gallons of crude

1 barrel of crude oil is approximately 42 gallons of crude oil

∴ 20000/9 gallons of crude = 20000/(9×42) barells of crude = 10000/

Which gives;

52\tfrac{172}{189} \, barrels \, of \, crude \, oil

Which is 52.9 barrels of crude oil

Hence the number of barrels of crude oil required to run the car for a year = 52.9 barrels of crude oil.

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Density of the mixture = mass of the mixture / volume of the mixture

Mass of the mixture = mass of antifreeze solution + mass of water.

Mass of antifreeze solution = density of the antifreeze solution * volume

Mass of antifreeze solution = 0.8g/ml * 5.1 l * 1000 ml / l = 4,080 g

Mass of water = density of water * volume of water = 1.0 g/ml * 3.8 l * 1000 ml / l = 3,800 g

Mass of mixture = 4080 g + 3800 g= 7880 g

Volume of mixture = volume of antifreeze solution + volume of water

Volume of mixture = 5100 ml + 3800 ml = 8900 ml

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3 years ago
Combustion analysis of toluene, a common organic solvent, gives 5.27 mg of co2 and 1.23 mg of h2o. if the compound contains only
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