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brilliants [131]
3 years ago
5

Need help please!!!

Mathematics
1 answer:
katrin2010 [14]3 years ago
4 0

Answer:

1. (A)

2.(C)

3. (C)

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Which expression is equivalent to (7x^2-4)(5x+7)
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Expand to get 35x^3+49x^2-20x-28


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Which of the following is the result of the equation below after completing the square and factoring? x^2-4x+2=10
Tamiku [17]

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Answer:

  B. (x-2)^2=12

Step-by-step explanation:

The constant that completes the square is the square of half the coefficient of the x-term. That value is (-4/2)^2 = 4.

There is already a constant of 2 on the left side of the equal sign, so we need to add 2 to both sides to bring that constant value up to 4.

  x^2 -4x +2 = 10 . . . . . . . given

  x^2 -4x +2 +2 = 10 +2 . . . . complete the square (add 2 to both sides)

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3 years ago
Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

P(1):\ 1 = \dfrac{1\cdot 2}{2}=1

So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

4 0
3 years ago
If f(x) = 2x2 5x, find f(3b).
frez [133]
F(x) = 2x^2 + 5x
f(3b) = 2(3b)^2 + 5(3b) = 2(9b^2) + 15b = 18b^2 + 15b
7 0
3 years ago
Please help me!!!!!!
Ivan

Answer:

please the answer is the third option

7 0
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