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3 years ago

A group of organisms that share similar characteristics

Chemistry

2 answers:

kondor19780726 [428]3 years ago

5 0

It is called a chromosone ?!!!!

ExtremeBDS [4]3 years ago

5 0

species, you can tell the difference of species if they do not live under those constraints prezygotic and postzygotic barriers.

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Starting with 1.5052g of BaCl2•2H2O and excessH2SO4, how many grams of BaSO4 can be formed?

muminat

1.5052g BaCl2.2H2O => 1.5052g / 274.25 g/mol = 0.0054884 mol
=> 0.0054884 mol Ba
This means that at most 0.0054884 mol BaSO4 can form since Ba is the limiting reagent. 
0.0054884 mol BaSO4 => 0.0054884 mol * 233.39 g/mol = 1.2809 g BaSO4

6 0

3 years ago

Read 2 more answers

According to the website of the National Aeronautics and Space Administration (NASA), the average temperature of the universe is

charle [14.2K]

Answer : The temperature in degree Celsius is, $-270.45^oC$

Explanation :

The conversion used for the temperature from Kelvin to degree Celsius is:

$^oC=K-273.15$

where,

$K$ = temperature in Kelvin

$^oC$ = temperature in centigrade

As we are given the temperature in Kelvin is, 2.7

Now we have to determine the temperature in Kelvin.

$^oC=K-273.15$

$^oC=2.7-273.15$

$^oC=-270.45$

Therefore, the temperature in degree Celsius is, $-270.45^oC$

3 0

3 years ago

What part is the independent variable and what part is the dependent variable in the scenario: The blood pressure of a soldier i

azamat

What part is the independent variable and what part is the dependent variable of the seminary the blood pressure of a soldier is measured while he’s resting soldiers and exposed to a stressful environment and his blood pressure is measured in

6 0

3 years ago

Sodium hydroxide reacts with aluminum and water to produce hydrogen gas: 2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H

lianna [129]

Answer:

The mass of hydrogen gas formed is 0.205 grams

Explanation:

Step 1: Data given

Mass of 1.83 grams of Al

Mass of NaOH = 4.30 grams

Molar mass of Al = 26.98 g/mol

Molar mass of NaOH = 40 g/mol

Step 2: The balanced equation:

2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2(g)

Step 3: Calculate moles of Al

Moles Al = mass Al / Molar mass Al

Moles Al = 1.83 grams / 26.98 g/mol

Moles Al = 0.0678 moles

Step 4: Calculate moles of NaOH

Moles NaOH = 4.30 grams / 40 g/mol

Moles NaOH = 0.1075 moles

Step 5: Calculate limiting reactant

For 2 moles of Al, we need 2 moles of NaOH

Aluminium is the limiting reactant. It will completely be consumed ( 0.0678 moles)

NaOH is in excess. There will react 0.0678 moles

There will remain 0.1075 - 0.0678 = 0.0397 moles

Step 6: Calculate moles of hydrogen

For 2 moles of Al, we need 2 moles of NaOH, to produce 3 moles of hydrogen

For 0.0678 moles of Al, there is produced 0.0678 *3/2 = 0.1017 moles of H2

Step 7: Calculate mass of H2

Mass of H2 = Moles H2 * Molar mass of H2

Mass of H2 = 0.1017 moles * 2.02 g/mol

Mass of H2 = 0.205 grams

The mass of hydrogen gas formed is 0.205 grams

6 0

3 years ago

Calculate the ph of a solution formed by mixing 200.0 ml of 0.30 m hclo with 300.0 ml of 0.20 m kclo. the ka for hclo is 2.9 × 1

velikii [3]

C(HClO) = 0,3 M.
V(HClO) = 200 mL = 0,2 L.
n(HClO) = c(HClO) · V(HClO).
n(HClO) = 0,06 mol.
c(KClO) = 0,2 M.
V(KClO) = 0,3 L.
n(KClO) = 0,06 mol.
V(buffer solution) = 0,2 L + 0,3 L = 0,5 L.
ck(HClO) = 0,06 mol ÷ 0,5 L = 0,12 M.
cs(KClO) = 0,06 mol ÷ 0,5 L = 0,12 M.
Ka(HClO) = 2,9·10⁻⁸.
This is buffer solution, so use Henderson–Hasselbalch equation:
pH = pKa + log(cs ÷ ck).
pH = -log(2,9·10⁻⁸) + log(0,12 M ÷ 0,12 M).
pH = 7,54 + 0.
pH = 7,54

6 0

3 years ago