How long would it take for 1.50 mol of water at 100.0 âc to be converted completely into steam if heat were added at a constant rate of 20.0 j/s ? express your answer to three significant figures and include the appropriate units?
1 answer:
To convert boiling water to steam, that would involve heat of vaporization. The heat of vaporization for water at atmospheric conditions is: ΔHvap = <span>2260 J/g. Molar mass of water = 18 g/mol Q = m</span>ΔHvap = (1.50 mol water)(18 g/mol)(<span>2260 J/g) = 61,020 J Time = Q/Rate = (61,020 J)(1 s/20 J) = 3051 seconds In order to express the answer in three significant units, let's convert that to minutes. Time = 3051 s * 1min/30 s = <em>102 min</em> </span>
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