Answer:
Maximum energy of the capacitor,
Explanation:
It is given that,
Dielectric constant of the parallel plate capacitor, k = 4.14
Area of cross section of each plate, 
Separation between the plates, d = 1.68 mm = 0.00168 m
The electric field between the plates, 
Let E is the maximum energy that can be stored in the capacitor. Its formula is given by :

C is the capacitance of the capacitor,



V is the potential difference,


V = 369.6 volts

So, the maximum energy that can be stored in the capacitor is
. Hence, this is the required solution.