Answer:
The maximum torque exerted by the person is, τ = 89.96 kg m² s⁻²
Explanation:
Given data,
The mass of the person riding a bike, m = 54 kg
The radius of rotation of the pedal, r = 17 cm
= 0.17 m
The torque exerted by the person is given by the formula,
τ = F r Sin θ
Where,
θ is the angle between F and R
The maximum torque exerted by the person is at θ = 90°
Therefore,
τ = F r
= m x g x r
= 54 x 9.8 x 0.17
= 89.96 kg m² s⁻²
Hence, the maximum torque exerted by the person is, τ = 89.96 kg m² s⁻²
the principle that in a series of stratified sedimentary rocks the lowest stratum is the oldest. 2. n. the displacement of any point due to the superposition <span>of wave systems is equal to the sum of the displacements of the individual waves at that point.</span>
Answer:
The Value is 
Explanation:
The explanation is shown on the first uploaded image
Answer:
303.29N and 1.44m/s^2
Explanation:
Make sure to label each vector with none, mg, fk, a, FN or T
Given
Mass m = 68.0 kg
Angle θ = 15.0°
g = 9.8m/s^2
Coefficient of static friction μs = 0.50
Coefficient of kinetic friction μk =0.35
Solution
Vertically
N = mg - Fsinθ
Horizontally
Fs = F cos θ
μsN = Fcos θ
μs( mg- Fsinθ) = Fcos θ
μsmg - μsFsinθ = Fcos θ
μsmg = Fcos θ + μsFsinθ
F = μsmg/ cos θ + μs sinθ
F = 0.5×68×9.8/cos 15×0.5×sin15
F = 332.2/0.9659+0.5×0.2588
F =332.2/1.0953
F = 303.29N
Fnet = F - Fk
ma = F - μkN
a = F - μk( mg - Fsinθ)
a = 303.29 - 0.35(68.0 * 9.8- 303.29*sin15)/68.0
303.29-0.35( 666.4 - 303.29*0.2588)/68.0
303.29-0.35(666.4-78.491)/68.0
303.29-0.35(587.90)/68.0
(303.29-205.45)/68.0
97.83/68.0
a = 1.438m/s^2
a = 1.44m/s^2
Answer:
a. 12.12°
b. 412.04 N
Explanation:
Along vertical axis, the equation can be written as
T_1 sin14 + T_2sinA = mg
T_2sinA = mg - T_1sin12.5 ....................... (a)
Along horizontal axis, the equation can be written as
T_2×cosA = T_1×cos12.5 ......................... (b)
(a)/(b) given us
Tan A = (mg - T_1sin12.5) / T_1 cos12.5
= (176 - 413sin12.5) / 413×cos12.5
A = 12.12 °
(b) T2 cosA = T1 cos12.5
T2 = 413cos12.5/cos12.12
= 412.04 N