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erma4kov [3.2K]
3 years ago
7

What section of dna are used in dna fingerprinting

Biology
1 answer:
Alja [10]3 years ago
7 0

Answer:

<em><u>R</u></em><em><u>epetitive DNA sequences "minisatellites." The two major uses for the information provided by DNA-fingerprinting analysis are for personal identification and for the determination of paternity. DNA fingerprinting is based on DNA analyzed from regions in the genome that separate genes called introns.</u></em>

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Snakes excrete waste products produced from the breakdown of food for energy.
Bingel [31]

The characteristic of life it represents is homeostasis.

<h3>What is homeostasis?</h3>

Homeostasis is the body's attempt to maintain a constant internal environment.

One of the major ways the body achieves homeostasis is through excretion, the process of removing wastes and excess water from the body.

Thus, when the snakes excrete waste products produced from the breakdown of food for energy, the characteristic of life it represents is homeostasis.

Learn more about homeostasis here: brainly.com/question/1046675

#SPJ1

3 0
1 year ago
Which of the following is an example of an animal that might be culled?
Dmitriy789 [7]

Answer:

D. Sami had low birth weight as a lamb but quickly grew into a large sheep.

Explanation:

The Sami lamb is an example of culled because it has the characteristics of quick growth. Culling is the process of separating organisms from a group of same type of organisms due to presence of desired or undesired characteristics. Sami sheep has a unique characteristic of having less weight at time of birth but having quick growth features that make to gain more weight and become large sheep so this sheep is removed from the population for its good traits.

7 0
3 years ago
Flock X Flock Y Flock Z Total Pieces of Food Eaten 57 153 90 Food Percentage* % % % Simulated Number of Birds in Flock for 2nd G
Zepler [3.9K]

Answer: The percentage would be 19%, 51% and 30%.

Explanation:

Since we have given that

Number of food eaten by X = 57

Number of food eaten by Y = 153

Number of food eaten by Z = 90

Total number of food eaten = 57+153+90=300

So, Food percentage of flock X = \dfrac{57}{300}\times 100=19\%

Food percentage of flock Y = \dfrac{153}{300}\times 100=51\%

Food percentage of flock Z = \dfrac{90}{300}\times 100=30\%

Hence, the percentage would be 19%, 51% and 30%.

9 0
3 years ago
Read 2 more answers
In the animal cell shown, label the structure A-E<br> Please help!
leonid [27]
Search up labels of a animal cell
5 0
1 year ago
A marine biologist dredges up a small animal from the bottom of the ocean. It is uniformly segmented, with short, stiff appendag
viva [34]

Answer:

The correct answer will be option-annelids

Explanation:

Annelids in the phylum of animals which includes about 22000 extant species. The animals of this group possess segmented body and thus are called ringed worms.

Each segment of the body contains the same organs and are usually found in the aquatic environment in the hydrothermal vents and the tidal zones. Some species are found in the terrestrial environment.

Since the biologist found the animal from the deep ocean with a segmented body and soft skin therefore, the animal belongs to the annelids.

Thus, option-annelids is the correct answer.

4 0
3 years ago
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