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Dmitrij [34]
3 years ago
10

How do you convert Kg's to Newtons?

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0
You don't convert kilograms to newtons.  By the time you've heard of these units, you know that 'kilogram' is a unit of mass, 'newton' is a unit of force or weight, and that mass and weight are different things.

Mass and force are <u>related</u> by Newton's second law: 

                       Force = Mass x acceleration .

From this simple formula, you can see that in order to relate a mass to a force, you need to know an acceleration.  And if the acceleration changes, then the relationship between the force and the mass also changes.  So there's no direct conversion.

ON EARTH ONLY, one kilogram of mass <em>weighs</em> 9.8 newtons. The acceleration that connects them is the acceleration of gravity on Earth.  In other places, with different gravitational accelerations, 1 kilogram weighs more or less newtons.

But they don't convert directly.  That would be like asking "How do you convert miles to miles-per-hour ?" 
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Read 2 more answers
Q¹=0,07Mc Q²=2C r=1,08 cm F=.......?
Nostrana [21]
The force (F) of attraction or repulsion between two point charges (Q1 and Q2) is given by the following rule:
F = <span>(k * q1 * q2) / (r^2)  where:
</span>q1 and q2 are the charges
k is coulomb's constant = 9 x 10^9<span> N. m</span>2/ C<span>2
</span>r is the distance between the two charges.

Applying the givens in the mentioned equation, we find that:
F = (9 x 10^9<span> x 0.07 x 10^6 x 2) / (0.0108)^2 = 1.08 x 10^19 n </span> 
5 0
3 years ago
Two particles execute simple harmonic motion of the same amplitude and frequency along close parallel lines. They pass each othe
deff fn [24]

Answer:

\theta_2 - \theta_1 = 156.93 degree

Explanation:

As we know that the displacement of the particle from the mean position is 1/5 times of its amplitude

so we have

y = A sin\omega t

y = \frac{A}{5}

so now we have

\frac{A}{5} = A sin\omega t

now we have

\theta_1 = 11.53 degree

so the phase other particle in opposite direction is given as

\theta_2 = 180 - 11.53 = 168.46 degree

so we have phase difference given as

\theta_2 - \theta_1 = 168.46 - 11.53

\theta_2 - \theta_1 = 156.93 degree

7 0
3 years ago
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