Answer:
0.4 s
Explanation:
The time that the ball is in the air can be found with the next formula:

where
is the initial velocity of the ball, in this case:

β is the angle: β = 29.0°
And g is the acceleration of gravity: 
Replacing all the values to find t, we have:

Thus, the ball is 0.4s in the air.
Distance D = 5 cm = 0.05m
Revolutions = 33.33 per min => t = 60 sec
Acceleration is v^2 / r, so first we need to find velocity
Velocity = (D x 3.14 x r) / t => (0.05 x 3.14 x 33.33) / 60
Velocity = 0.0872 m/s
Acceleration = v^2 / r = 0.0872^2 / 0.05 = 0.152.
C.reproducing is think and if wrong I'm so very sorry
To solve this problem we will apply the concepts related to the Force of gravity given by Newton's second law (which defines the weight of an object) and at the same time we will apply the Hooke relation that talks about the strength of a body in a system with spring.
The extension of the spring due to the weight of the object on Earth is 0.3m, then


The extension of the spring due to the weight of the object on Moon is a value of
, then

Recall that gravity on the moon is a sixth of Earth's gravity.




We have that the displacement at the earth was
, then


Therefore the displacement of the mass on the spring on Moon is 0.05m