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mojhsa [17]
3 years ago
15

The picture shows what happens when light shines on a tank of water.

Physics
2 answers:
balandron [24]3 years ago
7 0

Answer: I think it might D

Explanation:

Irina18 [472]3 years ago
3 0
I think it might be D
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The number of wave cycles that pass in one second is called the _______ of the wave.
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What is the tail of a comet made of
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A person can swim at 9 m/s. How long will it take them to swim 35 m
IRISSAK [1]

Answer:

v =  \frac{d}{t}   \\ t =  \frac{d}{v}  \\  =  \frac{35}{9} sec

5 0
3 years ago
A square loop of side length a =2.9 cm is placed a distance b = 1.2 cm from a long wire carrying a current that varies with time
daser333 [38]

Answer:

Explanation:

Magnetic field due to a long wire

B =  (  μ₀ / 4π ) x 2 I / r  ( I is current through the wire )

= (μ₀ Q t ) / ( 2 π r )                    [ I = Q t ]

b )  Magnetic field will change through the length of the square shaped loop . So we shall have to take the help of integration to calculate the flux through the loop.

Flux Φ = ∫ B dA

=∫ (  μ₀ / 4π ) x 2 I / r  dA

10⁻⁷ x 2 I ∫ a dr/r

2 x 10⁻⁷ x Qt x a [ ln (2.9+1.2) / 1.2  ]

4.6 x 10⁻⁷ x 2.9 x 10⁻² t  ln 4.1 / 1.2

16.4  x 10⁻⁹ t

Φ( t ) =  16.4 x 10⁻⁹ t

Induced emf  = dΦ( t ) / dt = 16.4 x 10⁻⁹ v

current

16.4 x 10⁻⁹  / 2.5

= 6.56 x 10⁻⁹

5 0
4 years ago
A car is traveling along a road, and its engine is turning over with an angular velocity of +188 rad/s. The driver steps on the
andreev551 [17]

Answer:

3751.80514 radians

Explanation:

\omega_f = Final angular velocity

\omega_i = Initial angular velocity

\alpha = Angular acceleration

\theta = Angle of rotation

t = Time taken

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=188\times 15.6+\dfrac{1}{2}\times 0\times 15.6^2\\\Rightarrow \theta=2932.8\ rad

The angular displacement would be 2932.8 rad

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=293\times 15.6+\dfrac{1}{2}\times 0\times 15.6^2\\\Rightarrow \theta=4570.8\ rad

The angular displacement would be 4570.8 rad

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{293-188}{15.6}\\\Rightarrow \alpha=6.73076\ rad/s^2

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\dfrac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\dfrac{293^2-188^2}{2\times 6.73076}\\\Rightarrow \theta=3751.80514\ rad

Actual value of the angular displacement is 3751.80514 radians

5 0
3 years ago
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