Question

An object is thrown with a horizontal velocity of 49mt/sec and a vertical velocity of 18.8 mt/sec. How long will the object take to return to earth. Please help asap

Answer 1

Answer:

The object takes 3.84 seconds to return to earth.

Explanation:

Projectile Motion

It's when an object projected above the ground at a certain velocity, moves along a curved path under the action of gravity.

The initial velocity has two components, given by:

$v_x=vo_x$

$v_y=vo_y-gt$

Where vox is the initial component of the velocity in the horizontal direction, voy is the initial component of the velocity in the vertical direction, and t is the time.

The object reaches a maximum height and then it returns to the ground. The time it takes to reach the maximum height can be calculated when the vertical component of the velocity is zero:

$vo_y-gt=0$

$\displaystyle t_m=\frac{vo_y}{g}$

The initial vertical component of the velocity is 18.8 m/s, thus:

$\displaystyle t_m=\frac{18.8}{9.8}=1.92~s$

The total time is double that time:

$t_t=2*1.92~s=3.84~s$

The object takes 3.84 seconds to return to earth.