It's a weak base bacause H C N is weak
intrusive
intrusive rocks have larger crystals
Answer:
Explanation:
Sn(WC)2
if it is tungsten carbide this should be correct but there are many versions of carbide
Sn(MC2)2
could also be possible
the 2 next to MC should be a subscript
Answer:
10. mol NaOH
Explanation:
2.5 M = 2.5 mol/L
2.5 mol/L * 4 L = 10. mol
It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:
Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH)
With the values put in: 0.35 x 45 = 0.35 x V(NaOH)
= 45 ml.
There is 45 ml of V(NaOH)
Let me know if you need anything else. :)
- Dotz
