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2 years ago

A 700- kg vehicle is traveling at the speed of 6m/s how much kinetic energy does it have ???

Physics

2 answers:

Sedbober [7]2 years ago

8 0

Kinetic energy = 1/2 x mass x velocity²

Kinetic energy = 1/2 x 700 x 6²

Kinetic energy = 12600 J

lutik1710 [3]2 years ago

6 0

<h2>Answer:</h2>

The kinetic energy will be 12600 J

<h2>Explanation:</h2>

As we know that

Kinetic energy = 1/2 (m) (v)²

By putting the values

Kinetic energy = 1/2 x 700 x 6²

We get

Kinetic energy = 12600 J

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$\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=\omega_i+\dfrac{\mu (-50)\times 0.52}{13.52}t\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{\mu (-50)\times 0.52}{13.52}\times 6\\\Rightarrow 0=6.28318-11.53846\mu\\\Rightarrow \mu=\dfrac{6.28318}{11.53846}\\\Rightarrow \mu=0.54454$

The coefficient of friction is 0.54454

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