<span>Weight is directly proportional to mass.</span>

The correct choice is ❝ A ❞
❖ whєn wє tαlk αвσut α pєndulum, ít gσєѕ thrσugh ❝ tσ αnd frσ ❞ mσtíσn, αlѕσ knσwn αѕ hαrmσníc mσtíσn. αѕ вєíng ín thє cαѕє σf α pєndulum, thєrє'ѕ α cσntínuσuѕ chαngє ín kínєtíc αnd pσtєntíαl єnєrgч.
❖ whєn thє вσв íѕ αt mєαn pσѕítíσn, ít hαѕ ítѕ mαхímum vєlσcítч, αnd thє nєt fσrcє αnd αccєlєrαtíσn αctíng σn ít íѕ zєrσ, thєrєfσrє ít hαѕ mαхímum kínєtíc єnєrgч αt thαt pαrtículαr ínѕtαnt.
❖ whєrє αѕ, íf thє вσв íѕ αt σnє σf thє єхtrєmє pσѕítíσnѕ, ítѕ vєlσcítч вєcσmєѕ zєrσ, αnd thє αccєlєrαtíσn αnd fσrcє αctíng σn ít íѕ mαхímum, ѕímcє ít hαѕ nσ vєlσcítч, thєrєfσrє ít hαѕ nσ kínєtíc єnєrgч αt thαt ínѕtαnt, thє σnlч єnєrgч ít hαѕ αt thαt tímє íѕ pσtєntíαl єnєrgч.
❖ ѕíncє thє mσvєmєnt íѕ cσntínuσuѕ, cσntínuσuѕ chαngє ín єnєrgч σccurѕ, вut thє ѕum σf вσth thє єnєgíєѕ rєmαínѕ cσnѕtαnt αt єvєrч ínѕtαnt.

Answer:
a) 1.67 m/s
b) 23kJ
Explanation:
We need to apply the linear momentum conservation formula, that states:

in this case:

the initital kinetic energy is:

and the final:

The energy lost is given by:

Answer:
Same
Explanation:
Let R be the resistance of the cell and E be the emf.
Let i be the current in the circuit.
i = E / R ..... (1)
Now emf and resistance be doubled.
so, i' = 2E/2R = E/R
So, i' = i (From equation (1)
Current remains same.
Answer:
<h3><em>
28.01m/s.</em></h3>
Explanation:
Given maximum height reached by the ball as H = 40 metres
Since the ball rises straight up when hit by a ball, then the angle of launch will be perpendicular to the ground and that is 90°.
To determine the upward speed of the ball in meters per second after it got struck by the bat, we will use the formula for calculating the maximum height according to projectile motion;
Maximum Height H =
where;
u is the speed of the ball
is the angle of launch
g is the acceleration due to gravity = 9.81m/s²
Substituting the given parameters into the formula;

<em>Hence the upward speed of the ball in meters per second after it got struck by the bat is 28.01m/s.</em>