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Morgarella [4.7K]
3 years ago
9

Assignment: The Meaning of Mitosis Exploration

Chemistry
2 answers:
NikAS [45]3 years ago
7 0

1. Mitosis is a process where a single cell divides into two identical daughter cells (cell division).


2. Mitosis is important because it plays an important part in the development of embryos, and it is important for the growth and developemet of our body as well.


3. The four phases of mitosis are: Prophase, metaphase, anaphase, and telophase.


all i know from there

hjlf3 years ago
5 0
1. Mitosis is a process where a single cell divides into two identical daughter cells (cell division).

2. Mitosis is important because it plays an important part in the development of embryos, and it is important for the growth and developemet of our body as well.

3. The four phases of mitosis are: Prophase, metaphase, anaphase, and telophase.

4. Two gap phases (G1 and G2); an S (for synthesis) phase, in which the genetic material is duplicated.

5. During S phase all of the chromosomes are replicated.

I hope that helps! c:
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The answer to number 3 is 0.5 and here's why:

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4 0
3 years ago
For elements 1–36, there are two exceptions to the filling order as predicted from the periodic table. draw the atomic orbital d
boyakko [2]

Here we have to draw the atomic orbital diagram of the elements present in the range of ¹H to ³⁶Kr having exception and its number of unpaired electrons present in the molecule.

The two exceptional elements are chromium (Cr) and Copper (Cu) the atomic orbital diagrams are-

²⁴Cr = 1s²2s²2p⁶3s²3p⁶3d⁵4s¹.

²⁹Cu = 1s²2s²2p⁶3s²3p⁶3d¹⁰4s¹.

The number of unpaired electrons in Cr and Cu are 6 and 1 respectively.

The atomic orbital diagram of the elements in periodic table is governed by the three rules or principles. Those are (i) The Aufbau principle, (ii) The Pauli exclusion principle and (iii) Hund''s rule of maximum multiplicity.

Among it the Aufbau principle explain the energy level of the atomic orbitals 1s < 2s 2p < 3s < 3P < 3d < 4s etc.

The Pauli's principle tells number of maximum electrons can be present in a particular orbital. As per the principle the s, p and d orbital can posses  maximum 2, 6 and 10 electrons.

the Hund's rules explains the extra stability of the half filled and full filled orbitals.

In ²⁴Cr (after ²³V: 1s²2s²2p⁶3s²3p⁶3d³4s²) the expected electronic configuration is 1s²2s²2p⁶3s²3p⁶3d⁴4s² having four unpaired electron but as the half filled d-orbital (5 electrons) is more stable thus it posses 1s²2s²2p⁶3s²3p⁶3d⁵4s¹ electronic configuration having 6 unpaired electrons.

In ²⁹Cu (after ²⁸Ni: 1s²2s²2p⁶3s²3p⁶3d⁸4s²) the expected electronic configuration is 1s²2s²2p⁶3s²3p⁶3d⁹4s² having 1 unpaired electron in d orbital, but due to high stability of the fulfilled d orbital (10 electrons) the atomic orbital diagram become 1s²2s²2p⁶3s²3p⁶3d¹⁰4s¹ having same number of unpaired electron is s orbital.

The two exceptional atomic orbital diagram of the element in between ¹H to ³⁶Kr is drawn and number of unpaired electrons are calculated.              

6 0
3 years ago
What is the oxidation number of sulfur in BaSO4?
____ [38]

Answer:

+6

Explanation:

We are given;

  • Compound BaSO₄

We are required to determine the oxidation number of S in the compound.

We need to know that;

  • The total oxidation number of this compound is Zero
  • Oxidation number of Ba metal is +2
  • Oxidation number of Oxygen atom is -2
  • There is 1 atom of Ba, 1 atom of S and 4 atoms of O in the compound.

Therefore; assuming oxidation number of S is x

Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0

2 + x - 8 = 0

x = 6 or +6

Thus oxidation number of Sulfur in BaSO₄ is +6.

7 0
3 years ago
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