Answer:
31.5mL
Explanation:
The following were obtained from the question:
C1 (concentration of stock solution) = 2M
V1 (volume of stock solution) =.?
C2 (concentration of diluted solution) = 0.630M
V2 (volume of diluted solution) = 100mL
Using the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:
C1V1 = C2V2
2 x V1 = 0.630 x 100
Divide both side by 2
V1 = (0.630 x 100) /2
V1 = 31.5mL
Therefore, 31.5mL of 2M solution of FeCl2 required
The two oxygen atoms share two pairs of electrons, so two covalent bonds hold the oxygen molecule together
Im pretty sure that the current will increase so the answer is A . Hope that helps
To solve this we use the
equation,
M1V1 = M2V2
<span>where M1 is the concentration of the stock solution, V1 is the
volume of the stock solution, M2 is the concentration of the new solution and
V2 is its volume.</span>
4.5 ( V1 ) = 3.0 ( 500 mL )
V1 = 333.33 mL needed of the 4.5 M phosphoric acid
Hope this answers the question. Have a nice day.
