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3 years ago

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How many molecules are in 97.21 grams of Sodium Chloride (NaCl)?

1 answer:

professor190 [17]3 years ago

6 0

1.66 is the answer because it’s is

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what is the effect of using higher concentration of sodium hydrogen carbonate on the rate of reaction?

Alex

Increasing the concentration of one or more reactants will often increase the rate of reaction. This occurs because a higher concentration of a reactant will lead to more collisions of that reactant in a specific time period.

Reaction rate increases with concentration, as described by the rate law and explained by collision theory. As reactant concentration increases, the frequency of collision increases. The rate of gaseous reactions increases with pressure, which is, in fact, equivalent to an increase in concentration of the gas.

7 0

2 years ago

Calculate the molar mass of iron(III) sulfide. Round your answer to the nearest 0.1 and include units to receive credit.

Igoryamba

Answer:

207.89g

Explanation:

The formula of the compound is:

Fe₂S₃

Find the molar mass of the compound;

Atomic mass of Fe = 55.845g/mol

S = 32.065g/mol

Now;

Molar mass of Fe₂S₃ = 2 (55.845) + 3 (32.065)

= 207.89g

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3 years ago

When being transferred from one container to another, liquids will

RoseWind [281]

A. I’m not positive but I’m pretty sure

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3 years ago

Read 2 more answers

A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. how much calcium is contained in 45.0 g of c

kolbaska11 [484]

In a sample of pure calcium fluoride of mass 15.0 g, 7.70 g of calcium is present. First convert the mass into number of moles as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass.

Molar mass of Ca is 40 g/mol, putting the values,

$n=\frac{7.70 g}{40 g/mol}=0.1925 mol$

Similarly, molar mass of $CaF_{2}$ is 78.07 g/mol thus, number of moles will be:

$n=\frac{15.0 g}{78.07 g/mol}=0.1921 mol$ .

Thus, 0.1921 mol of $CaF_{2}$ have 0.1925 mol of Ca, or 1 mole of $CaF_{2}$ will have approximately 1 mole of Ca.

Now, mass of Ca needs to be calculated in 45.0 g of $CaF_{2}$ . Converting mass into number of moles first,

$n=\frac{45.0 g}{78.07 g/mol}=0.5764 mol$

Thus, number of moles of Ca will also be 0.5764 mol, converting number of moles into mass,

$m=n\times M=0.5764 mol\times 40 g/mol=23.06 g$

Therefore, mass of Ca will be 23.06 g.

6 0

3 years ago

Please help, light equation<br><br> The second row, and explanation please.

Molodets [167]

What’s the question Bc I don’t understand what u are trying to ask

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3 years ago