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Delvig [45]
3 years ago
11

frank liked to buy packs of baseball cards. on 3 different days, he bought 3 packs. on 3 other days, he bought 4 packs each day.

After that he splits his packs with his 2 brothers. How many packs will they each have. Choose the expression that best matches this situation.
Mathematics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

First, frank buys 3 packs on 3 different days, so in those first 3 days he buys:

3*3 = 9 packs.

Then on other 3 days he buys 4 packs each day, so he has:

3*4 = 12 packs.

In total he haves:

9 + 12 = 21 packs.

Now he divides the packs with his 2 brothers (So we divide 21 packs between 3 people)

Then each brother gets:

N = 21/3 = 7 packs each.

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Answer:

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3 years ago
Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9
mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that \mu = 20.5, \sigma = 0.9

What percentage of full-term babies are between 19 and 21 inches long at birth?

The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then

X = 21

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.5}{0.9}

Z = 0.56

Z = 0.56 has a p-value of 0.7123

X = 19

Z = \frac{X - \mu}{\sigma}

Z = \frac{19 - 20.5}{0.9}

Z = -1.67

Z = -1.67 has a p-value of 0.0475

0.7123 - 0.0475 = 0.6648

0.6648*100% = 66.48%

66.48% of full-term babies are between 19 and 21 inches long at birth

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