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Wittaler [7]
3 years ago
15

Which of the following is a unit of volume in the metric system? (5 points)

Chemistry
1 answer:
Tresset [83]3 years ago
8 0
The answer is liter hope this helped :)
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Two very stable compounds, Freon-12 and Freon-14, are used as liquid refrigerants. A Freon-12 molecule consists of one carbon at
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81. There is 1 carbon, 2 chlorine and fluorine atoms in Freon 12. To draw them it forms a cross with C in the middle and Cl and F both on the opposite side. 
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82. Freon-12 and Freon-14 are called halocarbons or just halides. 


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3 years ago
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rewona [7]

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c

Explanation:

the correct answer would be answer c

6 0
2 years ago
A student is working on an assignment exploring the characteristics and uses of titanium. He notes in his assignment that it is
olga2289 [7]

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Acknowledge the source of relative weight of titanium.

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Titanium is a chemical element which durable form of metal. Titanium is 45% lighter than steel. Titanium is made by combination of multiple elements. Titanium is very difficult to extract and this is the reason this element is considered expensive. The students examining the titanium must record the weight of titanium before exploring the characteristics and properties.

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3 years ago
When a radioactive isotope undergoes Beta Decay, which of the following will NOT occur? PLEASE HELP ASAP! THANKS.
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3 0
3 years ago
What is the vapor pressure of CS2CS2 in mmHgmmHg at 26.5 ∘C∘C? Carbon disulfide, CS2CS2, has PvapPvap = 100 mmHgmmHg at −−5.1 ∘C
Digiron [165]

Answer: 26.5 mm Hg

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1= initial pressure at 26.5^oC = ?

P_2 = final pressure at -5.1^oC = 100 mm Hg

= enthalpy of vaporisation = 28.0 kJ/mol =28000 J/mol

R = gas constant = 8.314 J/mole.K

T_1= initial temperature = 26.5^oC=273+26.5=299.5K

T_2 = final temperature =-5.1^oC=273+(-5.1)=267.9K

Now put all the given values in this formula, we get

\log (\frac{P_1}{100})=\frac{28000}{2.303\times 8.314J/mole.K}[\frac{1}{299.5}-\frac{1}{267.9}]

\log  (\frac{P_1}{100})=-0.576

\frac{P_1}{100}=0.265

P_1=26.5mmHg

Thus the vapor pressure of CS_2CS_2 in mmHg at 26.5 ∘C is 26.5

7 0
4 years ago
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