Decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.
As we know that rate of reaction is directly proportional to the concentration of the reactant.
If we increase the concentration of H2 then the rate of reaction increases. So, we keep it constant. Therefore this option is wrong.
By removing the H₂O from the reaction vessel as it almost make no change in the reaction. This can be pursuited the reaction in which product again converted into product.
By increasing the temperature we increases the rate of reaction and equilibrium shift in the forward direction.
Thus, we concluded that by decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.
learn more about rate of reaction:
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1, neutralization of hydrochloric acid with sodium hydroxide
<span>,2. balanced </span>
<span>3. reactants are sodium hydroxide also called lye and hydrochloric acid which as a gas is hydrogen chloride, also stomach acid </span>
<span>products are water and sodium chloride, also called table salt</span>
Answer:
Activation energy for the uncatalyzed reverse reaction = 103 kJ/mol
Explanation:
Activation energy decreases from = 56 kj/mol to 35 kj/mol
products = 78 KJ lower in energy than reactants
Activation energy for the uncatalyzed reverse reaction = 103 kJ/mol
attached below are the sketches of approximate energy-level for both catalyzed and uncatalyzed reactions
Answer:
The thermal energy (heat) needed, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity 'c' from 20°C to 180°C is 160·m·c joules
Explanation:
The heat capacity, 'C', of a substance is the heat change, ΔQ, required by a given mass, 'm', of the substance to produce a unit temperature change, ΔT
∴ C = ΔQ/ΔT
ΔQ = C × ΔT
C = m × c
Where;
c = The specific heat capacity
ΔT = The temperature change = T₂ - T₁
∴ ΔQ = m × c × ΔT
Therefore, the thermal energy (heat) needed, ΔQ, to raise the temperature of oil of mass 'm' kilogram and specific heat capacity, 'c' from 20°C to 180°C is given as follows;
ΔQ = m × c × (180° - 20°) = 160° × m·c
ΔQ = 160·m·c joules
I assume the answer is chlorophyll (a or b) but could also be carotenoids.
