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Marina CMI [18]
3 years ago
15

A student took notes in class. - Uses high frequency sound waves - Creates images from echoes - Has many applications - Medical

- Pregnancy - Kidney stones - Cancer - Injury identification - Other - Cleaning - Identification of objects - Breakdown of bacteria - Production Which would be the best title for these notes?
Echolocation
Ultrasound Technology
Digital Signal
Analog Signal
Chemistry
2 answers:
SpyIntel [72]3 years ago
5 0
The correct option should be ultrasound technology (option B) because it is related to sonographers or ultrasound technicians. they are most likely with while pregnancy but they have plenty of uses, such as evaluating and diagnosis, many medical treatment for elderly patients. 
Fudgin [204]3 years ago
3 0
Ultrasound technology 
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The production of new skin cells to replace those that have been lost is an example of what characteristic of life?
Alchen [17]

The production of new skin cells is example of regeneration.

Regeneration is process of replacing or restoring not just skin cells, but also other cells in the human organism.

Skin regeneration is replacement of damaged tissue with new tissue.

There are two ways of skin regeneration:

1) reconstruction is a process of rebuilding of damaged skin cells

2) restoration is process of replacing broken cell skins

Epidermal stem cells are those who produces new daughter cell skins.

Epidermal stem cells are in the lowest layer of the skin.

More about skin: brainly.com/question/306377

#SPJ4

5 0
2 years ago
Which of the following statements best describes why a solution of 6.00 g of Ca(NO3)2?in 30.0 g of water has a greater boiling-p
sukhopar [10]
Boiling-point elevation is a colligative property.

That means, the the boiling-point elevation depends on the molar content (fraction) of solute.

The dependency is ΔTb = Kb*m

Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.

A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:

(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg =   50/molar mass

=> 200 / 50 = 4.

Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g  of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.

Or, what is the same, the solution with higher molality will have the higher boiling point.
5 0
3 years ago
Write the molecular formula of nitrate using criss cross method <br><br><br><br>​
exis [7]

Answer:

NO3 that is the answer to the question

8 0
3 years ago
(d)
Masteriza [31]

Explanation:

hope this helps you,

-s.

4 0
2 years ago
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
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