Answer:
Explanation:
Given
![N_1=1 rev/s](https://tex.z-dn.net/?f=N_1%3D1%20rev%2Fs)
angular velocity ![\omega =2\pi N_1=6.284 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D2%5Cpi%20N_1%3D6.284%20rad%2Fs)
Combined moment of inertia of stool,student and bricks ![=6\ kg.m^2](https://tex.z-dn.net/?f=%3D6%5C%20kg.m%5E2)
Now student pull off his hands so as to increase its speed to suppose
rev/s
After Pulling off hands so final moment of inertia is
![I_2=2\ kg-m^2](https://tex.z-dn.net/?f=I_2%3D2%5C%20kg-m%5E2)
Conserving angular momentum as no external torque is applied
![I_1\omega _1=I_2\omega _2](https://tex.z-dn.net/?f=I_1%5Comega%20_1%3DI_2%5Comega%20_2)
![6\times 6.284=2\times \omega _2](https://tex.z-dn.net/?f=6%5Ctimes%206.284%3D2%5Ctimes%20%5Comega%20_2)
![\omega _2=18.85\ rad/s](https://tex.z-dn.net/?f=%5Comega%20_2%3D18.85%5C%20rad%2Fs)
![N_2=3 rev/s](https://tex.z-dn.net/?f=N_2%3D3%20rev%2Fs)
Answer:
![v=1.93m/s](https://tex.z-dn.net/?f=v%3D1.93m%2Fs)
Explanation:
From the concept of fluids mechanics we know that if a tank has a hole at the bottom, the equation that we need to use is:
![v=\sqrt{2gh}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2gh%7D)
Since we know gravity and its hight
![v=\sqrt{2*(9.81m/s^{2})(0.19m) }=1.93m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2%2A%289.81m%2Fs%5E%7B2%7D%29%280.19m%29%20%7D%3D1.93m%2Fs)
It stays constant, because it's using that energy to change state
Answer:
The voltage si the nevery Hokage de Naruto y fue su amigo
Answer: The person sitting in the middle of the train sees the back of the train enter ing the tunnel before the front end comes out.
Explanation: