Answer:
B
Explanation:
That's the answer. Hope it helped!
Let us consider two bodies having masses m and m' respectively.
Let they are separated by a distance of r from each other.
As per the Newtons law of gravitation ,the gravitational force between two bodies is given as -
where G is the gravitational force constant.
From the above we see that F ∝ mm' and 
Let the orbital radius of planet A is
= r and mass of planet is
.
Let the mass of central star is m .
Hence the gravitational force for planet A is 
For planet B the orbital radius
and mass
Hence the gravitational force 
![f_{2} =G\frac{m*3m_{1} }{[2r_{1}] ^{2} }](https://tex.z-dn.net/?f=f_%7B2%7D%20%3DG%5Cfrac%7Bm%2A3m_%7B1%7D%20%7D%7B%5B2r_%7B1%7D%5D%20%5E%7B2%7D%20%7D)

Hence the ratio is 
[ ans]
Answer:
The coefficient is 0.90
Explanation:
Drawing a diagram makes thing easier, we will assume that the acceleration tends to zero because it start barely moving.

Answer:
0.23 J
Explanation:
k*(36 - 28) = 23
so k = 23/8 N/cm
W = k(32 - 28)²/2 = 23/8 * 4²/2 = 23 N-cm = 0.23 J
A transverse wave and a longitudinal wave.
Transverse:wave particles move at medium speed in perpendicular to the direction that the waves move
Longitudinal:wave particles move at medium speed in parallel to the direction that the wave moves
Hope this helps ^-^