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nata0808 [166]
3 years ago
15

What chemical element did hennig brand discover and what was he boiling down when he discovered it

Chemistry
1 answer:
lbvjy [14]3 years ago
8 0
Hennig Brand discovered Phosphorus while he was boiling Urine to produce gold.
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What is the hydronium ion concentration in an aqueous hydrobromic acid solution with a pH of 4.530?
Aloiza [94]

Answer:

2.951 × 10⁻⁵ M

Explanation:

Let's consider the acid reaction of hydrobromic acid according to Brönsted-Lowry acid-base theory.

HBr(aq) + H₂O(l) ⇒ Br⁻(aq) + H₃O⁺(aq)

Given the pH = 4.530, we can calculate the concentration of the hydronium ion using the following expression.

pH = -log [H₃O⁺]

[H₃O⁺] = antilog -pH = antilog -4.530 = 2.951 × 10⁻⁵ M

4 0
3 years ago
A helium balloon occupies a volume of 1.8 L at 5°C.<br>What volume will it occupy at 85.0°C?​
Zolol [24]
The volume of the balloon at 85.0°C would be 2.3L
5 0
3 years ago
Identify four techniques that take advantage of different physical
Neko [114]
Shii ion even knowwww
3 0
2 years ago
Which of the following will have the highest boiling point?
DerKrebs [107]

Answer:

0.1M NH3

Explanation:

The boiling point of aqueous solutions depend on the nature of intermolecular interactions present. KBr will yield an ionic solution but NH3 will yield a molecular solution having hydrogen bonds. The degree of hydrogen bonding in the aqueous solution will further increase with the concentration of the solution.

Remember that experimental data shows that hydrogen bonds are strong bonds that lead to a significant increase in the boiling point of solutions. Hence 0.1M NH3 solution will have a higher boiling point due to intermolecular hydrogen bonding in the solution.

8 0
3 years ago
How many moles of sucrose<br> are in 5.25x1029 sucrose<br> molecules? (in scientific notation)
Lorico [155]

Answer:

8.72 × 10^5 moles

Explanation:

To find the number of moles in 5.25 x 10^29 molecules of sucrose, we divide the number of molecules by Avagadro constant (6.02 × 10²³ molecules). That is;

no. of moles = no. of molecules ÷ 6.02 × 10²³ molecules

In this case of sucrose, no of moles contained is as follows;

5.25 × 10^29 ÷ 6.02 × 10²³

5.25/6.02 × 10^ (29-23)

0.872 × 10^6

= 8.72 × 10^5 moles

5 0
3 years ago
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