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swat32
3 years ago
10

What is the advantage of combining carbon from coal with steel?

Physics
1 answer:
____ [38]3 years ago
5 0

<span>The role of Carbon in steel is to increase hardness and tensile strength as well as response to heat treatment (hardenability). Increased amounts of carbon also reduces weldability. It is usually present to up to 2% carbon.</span>

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21. As a future healthcare professional, how could you use operant conditioning to minimize a patients’ fears or anxieties? (Rem
konstantin123 [22]

Answer:

Try to be their friend

Explanation:

Ask what sports they like

Connect to them

Tell them embarrassing stories that happened to you

Always say that everything will be okay

5 0
3 years ago
A 13.5 μF capacitor is connected to a power supply that keeps a constant potential difference of 24.0 V across the plates. A pie
liubo4ka [24]

Answer:

Explanation:

Capacitance of the capacitor = 13.5μF

Voltage across plate is 24V

Dielectric constant k=3.55.

a. Energy in capacitor is given by

E=1/2CV^2

We want to calculate energy without the dielectric substance

Given that C=13.5 μF and V=24V

The capacitance give is with dielectric so we need to remove it

C=kCo

Co=C/k

Then the Co=13.5μF/3.55

Co=3.803μF

Then

E=(1/2)×3.803×10^-6×24^2

E=1.1×10^-3J

E=1.1mJ

b. Energy in capacitor is given by

E=1/2CV^2

The capacitance given is with a dielectric, so we are going to apply it direct.

Given that C=13.5 μF and V=24V

Then

E=(1/2)×13.5×10^-6×24^2

E=3.89×10^-3J

E=3.9mJ

c. The energy without dielectric is 1.1mJ and the energy with dielectric is 3.9mJ

The energy increase when the dielectric material is added

d. Dielectrics in capacitors serve three purposes: to keep the conducting plates from coming in contact, allowing for smaller plate separations and therefore higher capacitances;

Therefore, Since dielectric allow higher capacitance, and energy of a capacitor is directly proportional to the capacitance, then the higher the capacitance the higher the energy.

6 0
4 years ago
The small spherical planet called "Glob" has a mass of 7.88×10^18 kg and a radius of 6.32×10^4 m. An astronaut on the surface of
Oksi-84 [34.3K]

Answer: The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down.

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Explanation: To find the answer, we need to know about the different equations of planetary motion.

<h3>How to find the initial speed of the rock as it left the astronaut's hand?</h3>
  • We have the expression for the initial velocity as,

                           v=\sqrt{2gh}

  • Thus, to find v, we have to find the acceleration due to gravity of glob. For this, we have,

                       g_g=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2}= 0.132

  • Now, the velocity will become,

                        v=\sqrt{2*0.132*1.44*10^3} =19.46 m/s

<h3>How to find the speed of the satellite?</h3>
  • As we know that, by equating both centripetal force and the gravitational force, we get the equation of speed of a satellite as,

                       v=\sqrt{\frac{GM}{r} } =\sqrt{\frac{6.67*10^{-11}*7.88*10^{18}}{1.45*10^5} } =3.624km/s

Thus, we can conclude that,

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Learn more about the equations of planetary motion here:

brainly.com/question/28108487

#SPJ4

3 0
2 years ago
Read 2 more answers
how does the pattern of heat transfer from Earth’s interior to Earth’s surface affect the Earth’s plates?
olga_2 [115]

Answer:

that it is bumpy or by the sun

Explanation:

4 0
3 years ago
Read 2 more answers
A box with a mass of 0.6-kg falls from a very tall building. While free-falling it is subjected to a frictional drag force given
rjkz [21]

Answer:

1.03m/s

Explanation:

According to the question

Fdrag = bv²

now Fdrag = weight of the box

that is Fdrag = mg

where m = mass of the box, 0.6 Kg

and g = acceleration due to gravity

thus,

Fdrag = bv²   becomes

mg = bv²

making v the subject of formula

v = \sqrt{\frac{mg}{b} }

v = \sqrt{\frac{0.6 * 9.8}{5.5} }

v = 1.03m/s

8 0
3 years ago
Read 2 more answers
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