The van der Waals equation for n moles of a gas is where P is the pressure, V is the volume, and T is the temperature of the gas
. The constant R is the universal gas constant and a and b are positive constants that are characteristic of a particular gas. a) If T remains constant, use implicit differentiation to find . b) Find the rate of change of volume with respect to pressure of 1 mole of carbon dioxide at a volume of V = 10 L and a pressure of P = 2.5 atm. Use a = 3.592 L2 -atm/mole2 and b = 0.04267 L/mole.
1 answer:
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Answer:
a. Vf = 39.24 [m/s]
b. Vf = 31.24 [m/s]
c. Vf = 47.24 [m/s].
Explanation:
To solve this problem we can use the following equation of kinematics. We have to keep in mind that the gravitational acceleration acts downwards, therefore when the rock falls towards the abyss it has the same direction of the acceleration and that is why the gravitational acceleration has a positive sign in the equation.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0 (when the rock is dropped)
g = gravitational acceleration = 9.81 [m/s²]
t = time = 4 [s]
a.
b.
In this particular situation, the acceleration will be taken as negative because the gravity is pointing in the opposite direction of the movement of the rock.
The negative sign in the answer tells us that the rock no longer moves up instead it does downwards when 4 seconds have passed.
c.