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4 years ago

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The van der Waals equation for n moles of a gas is where P is the pressure, V is the volume, and T is the temperature of the gas

. The constant R is the universal gas constant and a and b are positive constants that are characteristic of a particular gas. a) If T remains constant, use implicit differentiation to find . b) Find the rate of change of volume with respect to pressure of 1 mole of carbon dioxide at a volume of V = 10 L and a pressure of P = 2.5 atm. Use a = 3.592 L2 -atm/mole2 and b = 0.04267 L/mole.

1 answer:

Alexxandr [17]4 years ago

6 0

Answer:

(a)

dV/dp = $\frac{(nb - V)V^3}{2n^3ab + PV^3 - n^2av}$

(b) = -4.04L/atm

Explanation:

see the attached file

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A car drives 215km east and then 45km north. What is the magnitude of the cars displacement? Round you answer to nearest whole n

kifflom [539]

Answer: $219.65\ \text{km}$

Explanation:

Given

Car drives 215 km east and then 45 km North

Displacement is East direction is

$\Rightarrow \vec{r_1}=215\hat{i}$

Now, the displacement from that to 45 km North is given by

$\Rightarrow \vec{r_{21}}=45\hat{j}$

Net displacement is $\vec{r_2}$

$\Rightarrow \vec{r_2}=\vec{r_1}+\vec{r_{21}}\\\Rightarrow \vec{r_2}=215\hat{i}+45\hat{j}$

Magnitude of the displacement is

$\Rightarrow \left | r_{2} \right |=\sqrt{\left ( 215 \right )^2+\left ( 45 \right )^2}\\\Rightarrow \left | r_{2} \right |=\sqrt{48250}\\\Rightarrow \left | r_{2} \right |=219.65\ \text{km}$

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3 years ago

A person jumps out a fourth-story window 14 m above a firefighter safety net. The survivor stretches the net 1.8 m before coming

Monica [59]

Answer:

The deceleration is $a = - 76.27 m/s^2$

Explanation:

From the question we are told that

The height above firefighter safety net is $H = 14 \ m$

The length by which the net is stretched is $s = 1.8 \ m$

From the law of energy conservation

$KE_T + PE_T = KE_B + PE_B$

Where $KE_T$ is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )

and $PE_T$ is the potential energy of the before jumping which is mathematically represented at

$PE_T = mg H$

and $KE_B$ is the kinetic energy of the person just before landing on the safety net which is mathematically represented at

$KE_B = \frac{1}{2} m v^2$

and $PE_B$ is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

So the above equation becomes

$mgH = \frac{1}{2} m v^2$

=> $v = \sqrt{2 gH }$

substituting values

$v = 16.57 m/s$

Applying the equation o motion

$v_f = v + 2 a s$

Now the final velocity is zero because the person comes to rest

So

$0 = 16.57 + 2 * a * 1.8$

$a = - \frac{16.57^2 }{2 * 1.8}$

$a = - 76.27 m/s^2$

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3 years ago

When a transformer is step down then

Vera_Pavlovna [14]

Answer:

Hey!

Your answer should be D!

Explanation:

In a transformer Np / Ns is called the voltage ratio. If Ns is less than Np then Vs is less than Vp. This is called a step-down transformer as the voltage is reduced.

(source from google.com!)

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3 years ago

Which statements explain what happens at deep-ocean trenches? Check all that apply.

Yuki888 [10]

Answer:

the answers are the first and last option

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4 years ago

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A doppler fetal monitor is a hand-held ultrasound device that is used to detect a fetal heartbeat in prenatal care. The device w

Stolb23 [73]

Answer:

The maximum speed of the heart wall during the motion is 0.032 m/s

Explanation:

Given:

A = amplitude of vibration = 1.7 mm = 1.7x10⁻³m

f = frequency = 3 Hz

The angular velocity is:

$w=2\pi f=2\pi *3=18.85Hz$

The maximum speed of the heart wall during the motion is equal to:

$V=Aw=1.7x10^{-3} *18.85=0.032m/s$

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3 years ago