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Karolina [17]
3 years ago
11

The van der Waals equation for n moles of a gas is where P is the pressure, V is the volume, and T is the temperature of the gas

. The constant R is the universal gas constant and a and b are positive constants that are characteristic of a particular gas. a) If T remains constant, use implicit differentiation to find . b) Find the rate of change of volume with respect to pressure of 1 mole of carbon dioxide at a volume of V = 10 L and a pressure of P = 2.5 atm. Use a = 3.592 L2 -atm/mole2 and b = 0.04267 L/mole.

Physics
1 answer:
Alexxandr [17]3 years ago
6 0

Answer:

(a)

dV/dp = \frac{(nb - V)V^3}{2n^3ab + PV^3 - n^2av}

(b) = -4.04L/atm

Explanation:

see the attached file

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A ball is thrown horizontally from the top of a building 14.9 m high. The ball strikes the ground at a point 107 m from the base
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Answer:

1) t=1.743 sec

2)Vo=61.388  m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the  initial velocity of the ball that is=61.388  m/sec

4)Vf=17.08 m/s

Explanation:

1)From second equation of motion we get

h=Vit+(1/2)gt^2

here in case(a): Vi=0 m/s,h=14.9m,,put these values in above equation to find the time the ball is in motion

14.9=(0)*t+(1/2)(9.8)t^2

t^2=14.9/4.9

t^2=3.040 sec

t=1.743 sec

2) s=Vo*t

Putting values we get

107=Vo*1.743

Vo=61.388  m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the  initial velocity of the ball that is=61.388  m/sec

4)From third equation of motion we know that

Vf^2-Vi^2=2gh

here Vi=0 m/s,h=14.9 m

Vf^2=Vi^2+2gh=0+2(9.8)(14.9)

Vf^2=292.04

Vf=17.08 m/s

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