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frutty [35]
3 years ago
11

Please help anybody

Chemistry
1 answer:
Lana71 [14]3 years ago
4 0
21.9444....




To solve:
Distance / time!!
You can remember by a triangle...
/D\
| M T |
To find distance, MxT
To find mass, D/T
To find time, D/M
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How will you test for the gas which is liberated when hcl reacts with an active metal ?
DENIUS [597]
When HCl reacts with a metal, hydrogen gas will be evolved. To test this gas, insert a burning splinter into the outlet of gas, the flame will be extinguished with a pop sound. This will confirm the gas is hydrogen.
8 0
3 years ago
Hello<br>Thank you for not answering my question
julsineya [31]
**Visible confusion** no problem
4 0
3 years ago
What is the name of a solution whose concentration of solute is equal to the maximum concentration that is predicted from the so
faltersainse [42]

<u>Answer:</u> The correct answer is saturated solution.

<u>Explanation:</u>

For the given options:

Dilute solutions are defined as the solutions in which solute particles are present in less very amount than the solvent particles.

Unsaturated solutions are defined as the solutions where more and more of solute particles can be dissolved in the given amount of solvent.

Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent.  The concentration of the solute particles that can be dissolved in a solution is maximum.

Supersaturated solutions are defined as the solutions where more amount of solute particles are present than the solvent particles.

From the above information, we conclude that the given solution is saturated solution.

7 0
3 years ago
Read 2 more answers
Assume that the density and heat of combustion of E85 can be obtained by using 85 % of the values for ethanol and 15 % of the va
Alika [10]

Answer:

87.4 J

Explanation:

The density of the gasoline is 0.70 g/mL, and the density of the ethanol is 0.79 g/mL. The heat combustions (the heat released in a combustion reaction) are 5,400 kJ/mol for gasoline, and 1,370 kJ/mol for ethanol.

For 3.5 L of E85, the volumes of gasoline and ethanol are:

Vgasoline = 0.15 * 3.5 = 0.525 L = 5.25x10⁻⁴ mL

Vethanol= 0.85 * 3.5 = 2.975 L = 2.975x10⁻³ mL

The mass of gasoline and ethanol presented in that sample of E85 is the volume multiplied by the density:

mgasoline = 5.25x10⁻⁴ * 0.70 = 3.675x10⁻⁴ g

methanol = 2.975x10⁻³ * 0.79 = 2.35025x10⁻³ g

The number of moles for each substance is it mass divided by its molar mass. The molar masses are 114 g/mol for gasoline, and 46 g/mol for ethanol:

ngasoline = 3.675x10⁻⁴/114 = 3.224x10⁻⁶ mol

nethanol = 2.35025x10⁻³ /46 = 5.109x10⁻⁵ mol

The energy released is the heat combustion multiplied by the number of moles, so:

Egasoline = 5,400 * 3.224x10⁻⁶ = 0.0174 kJ = 17.4 J

Eethanol = 1,370 * 5.109x10⁻⁵ = 0.07 kJ = 70 J

So, the energy released by the E85 is the sum of the energy released by ethanol and gasoline:

The energy released by E85 = 87.4 J

8 0
3 years ago
This diagram shows the forces acting on a car. The center dot represents the car, and the arrows represent the forces acting on
Mariulka [41]

Answer : The correct option is B- Towards the left.

Solution : Given,

Force on car in upward direction, F_1 = 6000 N

Force on car in downward direction, F_2 = 6000 N

Force on car in right direction, F_3 = 5000 N

Force on car in left direction, F_4 = 6000 N

Force : Force is equal to the mass multiplied by the acceleration. The force is directly proportional to the acceleration.

Formula :  F =  m × a

where, F is force, m is mass and a is acceleration.

From the given diagram we conclude that the F_1 and F_2 are in opposite direction and the force acting on car are same. So, their net force is zero.

And in case of F_3 and F_4, the net force will not be zero because force acting on car are different. The car will accelerate towards left direction because F_4 is higher than the F_3.

So, the car will accelerate towards left direction.


3 0
3 years ago
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