A lab group was supposed to make mL of a acid solution by mixing a solution, a solution, and a solution. However, the solution w
as mislabeled, and was actually a solution, so the lab group ended up with mL of a acid solution, instead. What are the volumes of the solutions that should have been mixed?
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Alab group was supposed to make 14 mL of a 36% acid solution by mixing a 20% solution, a 26% solution, and a 42% solution. However, the 20% solution was mislabeled, and was actually a 10% solution, so the lab group ended up with 14 mL of a 34% acid solution, instead. If the augmented matrix that represents the system of equations is given below, what are the volumes of the solutions that should have been mixed? mL
Volume of 20% solution= ?
Volume of 26% solution = ?
Volume of 42% solution= ? Round to the nearest whole number ml
Answer:
Volume of 20% solution= 3 mL
Volume of 26% solution = 1 mL
Volume of 42% solution= 10 mL
Explanation:
Find attached of the calculations.
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Molarity of solution is mathematically expressed as,
M =
We know that volume = mass/density
Given: mass of solution = 100 g, Density = 1.34 g/ml
∴ volume = 100/1.34 = 88.49 ml = 0.08849 l
Also, we know that molecular weight of sucrose = 342.3 g/mol
∴M =
= 6.979 M
Thus, molarity of solution is 6.979 M
M =
We know that volume = mass/density
Given: mass of solution = 100 g, Density = 1.34 g/ml
∴ volume = 100/1.34 = 88.49 ml = 0.08849 l
Also, we know that molecular weight of sucrose = 342.3 g/mol
∴M =
= 6.979 M
Thus, molarity of solution is 6.979 M