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ipn [44]
3 years ago
11

THIS IS MEANT TO BE PHYSICS

Chemistry
1 answer:
kumpel [21]3 years ago
8 0
Answer number 2 is correct
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A solution has a oh- = 1 x 10-5 m what are the h30 and the ph of the solution
Deffense [45]

I think it's easiest to find the pOH from the given [OH-] first.

-log(1x10^-5)

pOH=5

Then find the pH.

pOH+pH=14

5+pH=14

pH=9

Then find the [H+] using the pH.

antilog(-9) (if you dont have an antilog button use 10^-9)

[H+]=1x10^-9

3 0
3 years ago
Read 2 more answers
Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in
Pani-rosa [81]

Answer:

666,480 Joules or 669.48 kJ

Explanation:

We are given;

  • Volume of water as 2.0L or 2000 ml

but, density of water is 1 g/ml

  • Therefore, mass of water is 2000 g
  • Initial temperature as 20 °C
  • Final temperature as 99.7° C

Required to determine the heat change

We know that ;

Heat change = Mass × Temperature change × specific heat

In this case;

Specific heat of water is 4.2 J/g°C

Temperature change is 79.7 °C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

                      = 669,480 Joules 0r 669.48 kJ

Thus, the heat change involved is 666,480 Joules or 669.48 kJ

5 0
3 years ago
Which of these is equal to 1 mole?
Ivahew [28]
44 g of carbon dioxide (CO2) 16 g of oxygen (O) Oxygen is diatomic but because there is written (O) I will said that 16 g is equal to one mole of oxygen atoms 
                                                                  ~Glad to help ^^

6 0
3 years ago
In 1983, a pilot miscalculated the fuel requirement for Air Canada Fight 143 from Montreal to Edmonton. Halfway through the flig
drek231 [11]

Answer:

27,397.23 L would be needed for a successful trip.

Explanation:

The problem gives us <u>the density (ρ) of the fuel,</u> by telling us that there are 803 g of fuel in 1 L, in which case:

ρ=\frac{mass}{Volume}=\frac{803g}{1L}  =803\frac{g}{L}

The required mass of fuel is 2.2 * 10⁴ kg, we can convert this value into g:

2.2 * 10⁴ kg * \frac{1000g}{1kg} = 2.2 * 10⁷ g

We calculate the required volume (V), using the mass and density:

803 g/L = \frac{2.2*10^{7}g }{V} \\V=\frac{2.2*10^{7}g }{803g/L}\\ V=27397.26 L

Thus 27,397.23 L would be needed for a successful trip.

5 0
3 years ago
What type of reaction is the following chemical reaction? SeO2 + 3Cl2 -&gt; SeCl6 + O2​
dem82 [27]

Answer:

This is a synthesis reaction.

Explanation:

This is because nothing is being swapped out, reactants are being combined and then form a product.

4 0
3 years ago
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