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ipn [44]
3 years ago
11

THIS IS MEANT TO BE PHYSICS

Chemistry
1 answer:
kumpel [21]3 years ago
8 0
Answer number 2 is correct
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How many moles of aluminum oxide will be formed from 17 moles of aluminum reaction?
Ainat [17]

Answer:

8.5 moles of Al₂O₃ will formed

Explanation:

Given data:

Number of moles of Al = 17 mol

Number of moles of Al₂O₃ formed = ?

Solution:

Chemical equation:

4Al  +  3O₂     →     2Al₂O₃

Now we will compare the moles of Al₂O₃  with Al.

                  Al            :            Al₂O₃      

                   4            :              2

                   17           :            2/4×17 = 8.5 mol

8.5 moles of Al₂O₃ will formed.    

7 0
3 years ago
PLEASE HELP ASAP!
LiRa [457]
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6 0
3 years ago
Which statement is true? (2 points) Select one: a. Geothermal power plants use the renewable resource of heat from within the Ea
love history [14]

The correct answer is A, since it is the only sensible answer.

5 0
3 years ago
Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu
nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,  

Cu(s)+Pb^{2+}(aq)\rightarrow Cu^{2+}(aq)+Pb(s)

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

E^0_{[Pb^{2+}/Pb]}=-0.13V

E^0_{[Cu^{2+}/Cu]}=+0.34V

E^0_{cell}=E^0_{cathode}-E^0_{anode}

E^0_{cell}=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cu^{2+}/Cu]}

E^0_{cell}=-0.13V-(0.34V)=-0.47V

Now we have to calculate the standard Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = -0.47 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times (-0.47))=+90710J/mole=+90.71kJ/mole\approx +91kJ/mole

Therefore, the standard Gibbs free energy is +91 kJ/mole

6 0
3 years ago
The mass of an object is 1,000 g. It has a volume of 100 mL. What is the density of the object? D= mass/volume
maxonik [38]

Answer:

10 g/ml

Explanation:

divide mass by volume means divide 1000 by 100 and your answer will be 10

4 0
3 years ago
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