Given :
Molarity of , M = 0.213 M .
To Find :
How many ml of 0.213 M of are required to deliver 66.4 mmol .
Solution :
Volume required :
So ,
Therefore , volume of required is 103.91 ml .
Hence , this is the required solution .
Answer:
0.228 mol FeO
Explanation:
2FeS2 + 5 O2----> 2FeO + 4SO2
from reaction 5 mol 2 mol
given 0.57 mol x
x = 0.57*2/5 = 0.228 mol FeO
Answer:
friend according to the question the answer is +3 ....
Answer:
Explanation:
You calculate the energy required to break all the bonds in the reactants.
Then you subtract the energy needed to break all the bonds in the products.
CH₃CH₂OH + 3O₂ ⟶ 2CO₂ + 3H₂O
Bonds: 5C-H 1C-C 1C-O 1O-H 3O=O 4C=O 6O-H
D/kJ·mol⁻¹: 413 347 358 467 495 799 467
Answer:
Atomic mass of Sulfur is 32.07.
Explanation:
The four common isotopes of sulfur have masses of 31.972 amu (95.00 % abundance), 32.971 amu (0.76 %), 33.967 amu (4.22 %), and 35.967 amu (0.014 %).
The atomic mass of sulfur will be calculated using atomic mass of there isotopes and their respective decimal abundance.
Atomic mass of sulfur = ∑ isotope * abundance
= {(95/100) *31.972} + {(0.76/100) *32.971} + {(4.22/100) *33.967} + {(0.014/100) *35.967}
= (0.95*31.972) + (0.0076*33.971) + (0.0422*33.967) + (0.00014*35.967)
= 30.3734 + 0.2582 + 1.4334 + 0.00504
= 32.07 amu
Relative atomic mass of sulfur is 32.07