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kotykmax [81]
2 years ago
13

How many particles of atoms are in 155 grams of silicon

Chemistry
1 answer:
sergeinik [125]2 years ago
3 0

Answer:

5,948

Explanation:

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A certain weak acid, ha, has a ka value of 6.0×10−7. calculate the percent ionization of ha in a 0.10 m solution.
joja [24]
For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:

Kd = c </span>× α²

α = √(Kd/c) × 100%

Kd = 6.0×10⁻⁷

c(HA) = 0.1M

α = √(6.0×10⁻⁷/0.1)  × 100% =  0.23%

So, in the solution, the acid <span>percent of ionization will be just 0.23%.</span>

5 0
3 years ago
I don't know how to solve this​
Misha Larkins [42]

For the first part, use the question M=mol/vol (liters)

To do this, you have the given 1.6 M solution

divide the 360g by the molar mass of ethanol (44.07) to get moles

360/44.07=8.16 mol

so

1.6M = 8.16 mol/x vol

volume: 5.1 Liters

8 0
3 years ago
What pressure will be produced when 2.0 moles of N2 gas is heated to 68oC in a container that holds 1.25 of gas?
Stella [2.4K]

The pressure of the nitrogen gas produced is determined as 44.77 atm.

<h3>What is the pressure of the Nitrogen gas?</h3>

The pressure of the nitrogen gas is determined from ideal gas equation, as shown below;

PV = nRT

P = nRT/V

where;

  • n is number of moles = 2 moles
  • R is ideal gas constant = 0.08205 L.atm/mol.K
  • T is temperature = 68⁰C = 68 + 273 = 341 K
  • V is volume = 1.25 L

P = (2 x 0.08205 x 341)/(1.25)

P = 44.77 atm.

Learn more about pressure here: brainly.com/question/25736513

#SPJ1

3 0
2 years ago
Weathering of rock and sedimentation ultimately lead to the formation of___
Inga [223]
Weathering of the rock and sedimentation are decomposition processes. Through time, the minerals in the rocks soften due to pressure and heat. So, they crumble down and reduce in terms of size. Once they do, they become sand or part of the soil. So, the answer is A.
6 0
3 years ago
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A cube of plastic 1.2x10^-5 km on a side has a mass of 1.1 g. what is its density in g/cm^3
Vesna [10]
Length of 1 side 1.2*10^-5km =1.2*10^-5*10^5 =1.2cm 

<span>volume of the cube (1.2)^3=1.728 cm^3 </span>

<span>density= mass/volume= 1.1/1.728=0.636 g/cm^3</span>
7 0
3 years ago
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