Answer:
The deflection of the spring is 34.56 mm.
Explanation:
Given that,
Diameter = 10 mm
Number of turns = 10
Load = 200 N
We need to calculate the deflection
Using formula of deflection
Put the value into the formula
Hence, The deflection of the spring is 34.56 mm.
Answer:
distance r from the uranium atom is 18.27 nm
Explanation:
given data
uranium and iron atom distance R = 44.10 nm
uranium atom = singly ionized
iron atom = doubly ionized
to find out
distance r from the uranium atom
solution
we consider here that uranium electron at distance = r
and electron between uranium and iron so here
so we can say electron and iron distance = ( 44.10 - r ) nm
and we know single ionized uranium charge q2= 1.602 × C
and charge on iron will be q3 = 2 × 1.602 × C
so charge on electron is q1 = - 1.602 × C
and we know F =
so now by equilibrium
Fu = Fi
=
put here k = and find r
=
r = 18.27 nm
distance r from the uranium atom is 18.27 nm