the earth exerts a gravitational force
 
        
                    
             
        
        
        
Answer:
time required after impact for a puck is 2.18 seconds
Explanation:
given data 
mass = 30 g = 0.03 kg
diameter = 100 mm = 0.1 m
thick = 0.1 mm = 1 × m
 m
dynamic viscosity = 1.75 × Ns/m²
 Ns/m²
air temperature = 15°C
to find out
time required after impact for a puck to lose 10%
solution
we know velocity varies here 0 to v 
we consider here initial velocity = v
so final velocity = 0.9v
so change in velocity is du = v
and clearance dy = h
and shear stress acting on surface is here express as 
 = µ 
so 
 = µ   ............1
   ............1
put here value
 = 1.75× ×
 × 
 = 0.175 v
and 
area between air and puck is given by 
Area =  
 
area  =   
 
area = 7.85 ×  m²
 m²
so 
force on puck is express as 
Force = × area 
force = 0.175 v × 7.85 × 
force = 1.374 ×  v
 v    
and now apply newton second law
force = mass × acceleration
- force = 
- 1.374 ×  v =
 v = 
t =  
time = 2.18 
so time required after impact for a puck is 2.18 seconds
 
        
             
        
        
        
If we will connect the resistors 2ohms, 3ohms, 5ohms in series and the 10ohms resistance parallel then we get equivalent resistance of 5 ohms.
The equivalent circuit is,
R equivalent for the series connection is,

The equivalent resistance is 5 ohms.
So your friend is saying true.
 
        
             
        
        
        
Answer:
I_v = 2,700 W / m^2
I_m = 610 W / m^2
I_s = 16 W / m^2
Explanation:
Given:
- The Power of EM waves emitted by Sun P_s = 4.0*10^26 W
- Radius of Venus r_v = 1.08 * 10^11 m
- Radius of Mars r_m = 2.28 * 10^11 m
- Radius of Saturn r_s = 1.43 * 10^12 m
Find:
 Determine the intensity of electromagnetic waves from the sun just outside the atmospheres of (a) Venus, (b) Mars, and (c) Saturn.
Solution:
- We know that Power is related to intensity and surface area of an object follows:
                                         I = P / 4*pi*r^2
Where, A is the surface area of a sphere models the atmosphere around the planets.
a) 
- The intensity at the surface of Venus is calculated as:
                                        I_v = P_s / 4*pi*r^2_v
                                        I_v = 4.0*10^26 / 4*pi*(1.08*10^11)^2
                                        I_v = 2,700 W / m^2
b)
- The intensity at the surface of Mars is calculated as:
                                        I_m = P_s / 4*pi*r^2_m
                                        I_m = 4.0*10^26 / 4*pi*(2.28*10^11)^2
                                        I_m = 610 W / m^2
c)
- The intensity at the surface of Saturn is calculated as:
                                        I_s = P_s / 4*pi*r^2_s
                                        I_s = 4.0*10^26 / 4*pi*(1.43*10^12)^2
                                        I_s = 16 W / m^2
 
        
             
        
        
        
Answer:
The flow of electric charge
Explanation:
Electricity:It is defined flow of electric charge.
It is defined as the flow of charge per unit time.
Electric charge can be negative or positive .
Mathematical representation :
If charge Q flowing through the conductor and time taken in flow of charge is t seconds.
Then, current
S.I unit of current is Ampere.It is scalar quantity.
Answer:The flow of electric charge.