Answer:
The natural frequency will be 228.11 rad/sec
Explanation:
We have given Inductance L = 0.048 Henry
And the capacitance C = 0.0004 farad
We have to find natural frequency
When only inductor and capacitor is present in the circuit then it is known as LC circuit and Natural frequency of LC circuit is given by ![\omega _0=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.048\times 0.0004}}=228.21\ rad/sec](https://tex.z-dn.net/?f=%5Comega%20_0%3D%5Cfrac%7B1%7D%7B%5Csqrt%7BLC%7D%7D%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B0.048%5Ctimes%200.0004%7D%7D%3D228.21%5C%20rad%2Fsec)
So the natural frequency will be 228.21
Answer:
The answer to the question is
The object would fall 57.625 m in the first 5 seconds
Explanation:
To solve the question, we note that
the height of fall = 490 ft = 149.352 m
Time to touch the ground = 7 seconds
We are required to find out how far the object falls in the first 5 seconds
We apply the relation
S = u·t + 0.5×g·t ² = We then have
149.352 = U×7+0.5*9.81*49 From where u = -13 m/s
Therefore to find how far it falls in the first 5 seconds, we have
-13*5 + 0.5*9.81*25 = 57.625 m
Answer:
<h2><em>
15.00124mmHg</em></h2>
Explanation:
Pressure is defined as the ratio of force applied to an object to its area.
Pressure = Force/Area
Given parameters
Force = 0.242N
Area = 1.21cm²
Required parameters
Pressure = 0.242/1.21
Pressure = 0.2N/cm²
Using the conversion to convert the pressure to mmHg
1N/cm² = 75.0062mmHg
0.2N/cm² = y
y = 0.2 * 75.0062
y = 15.00124mmHg
<em>Hence the pressure in mmHg is 15.00124mmHg</em>
The answer to your question is 5:7