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muminat
3 years ago
6

Which best describes the transition from gas to liquid? (2 points) Select one: a. Energy must be removed because particles in li

quid move more slowly. b. Energy must be added because particles in liquid move more quickly. c. Energy is neither added nor removed in this phase transition. d. Energy is either removed or added, depending on the type of particles.
Physics
2 answers:
Alenkinab [10]3 years ago
8 0

Which best describes the transition from gas to liquid?

gas is @ higher energy state than liq. so the transition must remove energy. so ans is  a. Energy must be removed because particles in liquid move more slowly.

VashaNatasha [74]3 years ago
6 0

The best description of the transition from gas to liquid is a. Energy must be removed because particles in liquid move more slowly.

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Two cars are travelling in the same direction on a road. The blue car is travelling at 50 m/s in front of the red car, which is
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Explanation:

The speed of the red car, relative to the blue car, is:

v = 75 m/s − 50 m/s

v = 25 m/s

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3 years ago
Analyze the data to identify the mathematical relationship between the
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C.) Wave B has about 2.25 times more energy than wave A

Explanation:

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2 years ago
When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching __________. A. an altitude of 3100
frutty [35]

Answer:

When flying the LNAV Approach, the missed approach point (MAP) would be indicated by reaching:

C. the RW30 waypoint.

Explanation:

  • In Aviation, LNAV stands for Lateral Navigation. The option a is incorrect as an altitude of 3100 feet refers to the decision altitude not the missed approach point.
  • The option b is incorrect as a distance of 1.5 NM  to RW30 referring to the Visual descent point (VDP) is 1.5 nautical miles for the Runway (RW) 30 from threshold.
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8 0
3 years ago
PLZZ HELP ASAP!!
Nimfa-mama [501]
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8 0
3 years ago
A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

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3 years ago
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