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Galina-37 [17]
3 years ago
12

In a transfer of energy, there is no change in the energy's, what?

Physics
1 answer:
frutty [35]3 years ago
7 0

I think it is there is no change in the energy's sunlight

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The heliocentric system gained support when Galileo observed that _____.
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Venus goes through phases similar to those of earths moon.
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3 years ago
As a hiker in Glacier National Park, you are looking for a way to keep the bears from getting at your supply of food. You find a
Lorico [155]

Answer:

Acceleration of the bags is 0.861 m/s²

Explanation:

Given:

Mass of the rock, m = 22.5 kg = mass of the food

Slope, Θ = 55.5°

Now, from the figure, we have

T - mgsinΘ = ma            ...................(1)

'a' is the acceleration of the mass

where T is the tension

also for the second mass, we have

mg - T = ma

now substituting the value of T from the equation (1) we get

mg - (ma + mgsinΘ) = ma

or

mg(1 - sinΘ) = (m + m)a

or

a = \frac{mg(1 - sin\theta)}{2m}

on substituting the values we get

a = \frac{9.8\times (1 - sin55.5^o)}{2}

or

a = 0.861 m/s²

Hence, the acceleration of the bags is 0.861 m/s²

7 0
3 years ago
What is the Potential energy of a magnetic generator
sergiy2304 [10]

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4 years ago
I need help. which interaction does not take place due to field forces
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Answer:

Explanation:

Answer D. Interaction between a pen and paper while you write

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3 years ago
What constant acceleration in si units must a car have to go from zero to 60 mph in 10s. what fraction of g is this?
Sophie [7]

The acceleration of the car in SI units is <u>2.68m/s².</u>

The acceleration is <u>0.27</u> times the acceleration due to gravity g.

Convert the speed in mph into m/s.

1 mile = 1609 m and 1h = 3600 s.

Therefore,

v=(\frac{60 miles}{1 h} )(\frac{1609 m}{1 mile} )(\frac{1h}{3600s)} =26.82m/s

Acceleration is the rate of change of velocity. The car starts from rest , its initial velocity u = 0 and accelerates to a velocity v of 26.82 m/s in 10 s.

Use these values in the equation and calculate the acceleration.

a=\frac{v-u}{t} \\ =\frac{(26.82 m/s)-(0m/s)}{10s} \\ =2.682 m/s^2

Thus the car accelerates at a rate of <u>2.68 m/s².</u>

The acceleration due to gravity g on Earth has a value 9.81 m/s².

Find the ratio\frac{a}{g}

\frac{a}{g} =\frac{2.682m/s^2}{9.81m/s^2} \\ =0.27&#10;a=0.27g

The car's acceleration is <u>0.27 times the value of g.</u>

3 0
3 years ago
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