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Galina-37 [17]
3 years ago
12

In a transfer of energy, there is no change in the energy's, what?

Physics
1 answer:
frutty [35]3 years ago
7 0

I think it is there is no change in the energy's sunlight

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A cylinder of radius r=10.0 cm and height h=20.0 cm
Olenka [21]
D I think is the correct answer
If the cylinder is slightly
7 0
2 years ago
A high-jumper, having just cleared the bar, lands on an air mattress and comes to rest. Had she landed directly on the hard grou
Hoochie [10]

Answer:

e. the air mattress exerts the same impulse, but a smaller net avg force, on the high-jumper than hard-ground.

Explanation:

This is according to the Newton's second law and energy conservation that the force exerted by the hard-ground is more than the force exerted by the mattress.

The hard ground stops the moving mass by its sudden reaction in the opposite direction of impact force whereas the mattress takes a longer time to stop the motion of same mass in a longer time leading to lesser average reaction force.

<u>Mathematical expression for the Newton's second law of motion is given as:</u>

F=\frac{dp}{dt} ............................................(1)

where:

dp = change in momentum

dt = time taken to change the momentum

We know, momentum:

p=m.v

Now, equation (1) becomes:

F=\frac{d(m.v)}{dt}

<em>∵mass is constant at speeds v << c (speed of light)</em>

\therefore F=m.\frac{dv}{dt}

and, \frac{dv}{dt} =a

where: a = acceleration

\Rightarrow F=m.a

also

F\propto \frac{1}{dt}

so, more the time, lesser the force.

<em>& </em><u><em>Impulse:</em></u>

I=F.dt

I=m.a.dt

I=m.\frac{dv}{dt}.dt

I=m.dv=dp

∵Initial velocity and final velocity(=0), of a certain mass is same irrespective of the stopping method.

So, the impulse in both the cases will be same.

4 0
3 years ago
If a pitcher throws a baseball 10 m in 30 seconds - what would be the average speed of the baseball
dangina [55]
S = d/t
S = 10m/30s
S = 0.33m/s
6 0
3 years ago
A 0.145 kg baseball is thrown with a velocity of 25.0 m/s. How much work was done on the baseball to bring it from rest to 25.0
sergey [27]

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W=\frac{1}{2}m(v^2-u^2)

Using the formula

Work done, W=\frac{1}{2}(0.145)((25)^2-0)

Work done=\frac{1}{2}(0.145)(625)

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J

3 0
3 years ago
Draw the graphs for exothermic and endothermic reactions Label: axes, reactants, products, Energy of reaction, heat energy chang
nikdorinn [45]

Answer:

axes, reactants, products, Energy of reaction, heat energy

Explanation:

axes, reactants, products, Energy of reaction, heat energyaxes, reactants, products, Energy of reaction,grreactantsaphs heat energy

3 0
3 years ago
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