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2 years ago

VERY EASY QUESTION!!!!!! 20 POINTS!!!!!!!!

Physics

2 answers:

liubo4ka [24]2 years ago

8 0

Remark

There fewer people who see it the better if you are still a little uncertain about what to say or how to say it.

Given the remark, I think this is the place to start. Mothers are especially tolerant about listening to a first time speech. The criticism is very light. You will benefit most by hearing what it sounds like. I would pick A as the answer.

You have an awful lot of nerve if you are going to talk in front of an audience that large with an unprepared speech. Good luck.

At a science fair is not a bad choice. The groups are small, and you will get to explain your project many times before you see a judge. That will give you the necessary experience to polish what you have to say.

How do you feel about talking in front of classmates with a teacher giving you a mark? Not the best place to start.

Conclusion. Please Read

Where you start depends on what you are talking about. The science fair option is a good one if that is your intended audience. For all other assignments, I'd pick A. If this is a question that actually came from a physics class then pick C.

slamgirl [31]2 years ago

4 0

C. at a science fair

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3 years ago

A 1-kg iron frying pan is placed on a stove. The pan increases from 20°C to 250°C. If the same amount of heat is added to a pan

sergejj [24]

Here mass of the iron pan is given as 1 kg

now let say its specific heat capacity is given as "s"

also its temperature rise is given from 20 degree C to 250 degree C

so heat required to change its temperature will be given as

$Q = ms \Delta T$

$Q = 1*s*(250 - 20)$

$Q = 1*s*230$

now if we give same amount of heat to another pan of greater specific heat

so let say the specific heat of another pan is s'

now the increase in temperature of another pan will be given as

$Q = ms'\Delta T$

$1*s*230 = 1* s' * \Delta T$

now we have

$\Delta T = (\frac{s}{s'})*230$

now as we know that s' is more than s so the ratio of s and s' will be less than 1

And hence here we can say that change in temperature of second pan will be less than 230 degree C which shows that final temperature of second pan will reach to lower temperature

So correct answer is

<u>A) The second pan would reach a lower temperature.</u>

3 0

2 years ago

Read 2 more answers

A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a

GuDViN [60]

Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

Explanation:

From Newton's second law, F = mg and also from coulomb's law F= Eq

Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1

Again, in a projectile motion, the time of flight (T) is given as

T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

$T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}$

Charge of proton = 1.6 X 10⁻¹⁹ C

Mass of proton = 1.67 X 10⁻²⁷ kg

E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°

Solving for T;

$T = \frac{(1.67X10^{-27}* 2*3X10^4sin 30}{400*1.6X10^{-19}}$

T = 7.83 X10⁻⁷ s

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2 years ago