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mihalych1998 [28]
3 years ago
8

The former soviet union launched the first artificial earth satellite. What is the name of this satelitte?

Physics
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

Sputnik I.

Explanation:

The Soviet Union (former) launched the first artificial earth satellite called Sputnik I on October 4, 1957.

It had a diameter of 58 cm and it weighed 83.6 kg. It had an orbital period of 5880 seconds around the earth. It orbited the 11 weeks (officially 3 weeks but then, its battery died and it orbited for 8 weeks before falling back into the earth's atmosphere).

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What process is used in this example? You have learned that all living things use energy. Your dog is a living thing. She must u
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Option B.) Deductive Reasoning
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A 19.0-kg cart is moving with a velocity of 7.20 m/s down a level hallway. A constant force of -13.0 N acts on the cart and its
gulaghasi [49]

Answer:

a. -369.36J

b. -123.9J

c. 9.52m

Explanation:

From the expression for kinetic energy

K. E=1/2mv^2

Since the mass is constant, but the velocity changes. Hence the change in kinetic energy is

K.E=1/2*19(3.6²-7.2²)

K.E= -369.36J

b. to determine the workdone by the force,we determine the distance moved.

But the acceleration is from

F=ma ,

a=f/m

a=-13/19

0.68m/s²

the distance moved is

s=v²/2a

s=3.6²/2*0.68

s=9.52m

Hence the work done is

W=force * distance

W=-13*9.52

W=-123.9J

d. the distance moved is

s=v²/2a

s=3.6²/2*0.68

s=9.52m

4 0
3 years ago
Read 2 more answers
A baseball player hits a baseball with a bat. The mass of the ball is 0.25 kg. The ball accelerates at 200 m/s2. What is the for
Brums [2.3K]

Answer:

50N

Explanation:

Force (N) = mass (kg) × acceleration (m/s²)

0.25kg times 200m/s² = 50N

6 0
3 years ago
What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo
Pachacha [2.7K]

Answer:

14,300 lines per cm

Explanation:

Answer:

14,300 cm per line

Explanation:

λ400 nm to 400nm

We can find the maximum number of lines per centimeter, which is reciprocal of the least distance separating two adjacent slits, using the following equation.

mλ = dsin (θ)

In this equation,

m is the order of diffraction.

λ is the wavelength of the incident light.

d is the distance separating the centers of the two slits.

θ is the angle at which the mth order would diffract.

To find the least separation that allows the observation of one complete order of spectrum of the visible region, we use the maximum wavelength of the visible region is 700 nm.

d =  mλ / sin (θ)

As we want the distance d to be the smallest then sin (θ) must be the greatest, and the greatest value of the sin (θ) is 1. For that we also use the longest wavelength because using the smallest wavelength, the longest wavelength would not be diffracted.

d =  mλ / sin (θ)

d =  1 x 700nm / 1

  = 700 nm

So, the least separation that would allow for the possibility of observing complete first order of the visible region spectra is 700 nm, and knowing the least separation we can find the maximum number of lines per cm, which is the reciprocal of the number of lines per cm.

n = 1/d

   = 1 / 700 x 10^{-9}

  = 1, 430,000 lines per m  

  =  14,300 lines per cm

<u>The maximum number of lines per cm, that would allow for the observation of the complete first order visible spectra.</u>

5 0
3 years ago
Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then
kari74 [83]

The density of an object is the mass of the object divided by its volume.

Remember that mass of an object is the amount of matter that the object contains. The unit for mas in the standard international unit system is the kilogram (kg), which is 1000 grams; the unit of mass in the US is the pound (lb), which is 453.592 grams.

The volume of an object is the amount of space that the object occupies. The unit for volume in the standard international unit system are the cubic meter (m^3) and the liter (L); 1 cubic meter equals 1000 liters.

The density of an object is the quantity of mass of the object per unit of its volume. The unit for mas in the standard international unit system is the kilogram per cubic meter (\frac{kg}{m^3}).

Now, lets create our hypothesis:

If the mass and the volume of and object are known, then its density can be calculated dividing the object's mass by its volume.

We can conclude that the density of an object can be obtained by dividing its mass by its volume.

4 0
3 years ago
Read 2 more answers
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