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scZoUnD [109]
3 years ago
12

How could the appearance of a substance change with out it becoming a different substance

Chemistry
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer:

When water melts from ice to liquid, or boils and becomes a gas, it is still water.

Explanation:

You might be interested in
How many protons z and how many neutrons n are there in a nucleus of the most common isotope of silicon, 2814si? separate your a
Maksim231197 [3]
The Atomic Number and Atomic Mass of ²⁸Si₁₄ are 14 and 28 respectively.

Atomic Number:
                         Atomic Number of Element is the Number of Protons contained by the Element. So, there are 14 Protons in ²⁸Si₁₄.

Atomic Mass:
                     Atomic Mass of Element is the total number of Protons and Neutrons present in the Nucleus of that element.
So,
                    Atomic Mass  =  # of Protons + # of Neutrons

As the Atomic mass of ²⁸Si₁₄ is 28 and it has 14 protons, So # of Neutrons are calculated as,

                     # of Neutrons  =  Atomic Mass - # of Protons

                     # of Neutrons  =  28 - 14

                     # of Neutrons  =  14

Result:
             In ²⁸Si₁₄ Number of Neutrons are 14, Number of Protons are 14.

                                             Z  =  14 , n  =  14
3 0
3 years ago
A container with a volume of 893L contains how may moles of air at STP?
Vadim26 [7]

Answer:

i think 54

Explanation:

7 0
3 years ago
Calculate the ΔHrxn for the following
seropon [69]

Answer: alright now listen fe203(s)=567.66666

Explanation:

8 0
3 years ago
Show how acid and base give below dissociates in water <br>HNO3​
lara31 [8.8K]
The answer is b thank me later :)
3 0
2 years ago
Suppose of ammonium nitrate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of ammonium c
Marta_Voda [28]

Answer:

Final molarity of ammonium cation in the solution = 0.16 M

Explanation:

Complete Question

Suppose 2.59 g of ammonium nitrate is dissolved in 200. mL of a 0.40M aqueous solution of sodium chromate. Calculate the final molarity of ammonium cation in the solution. You can assume the volume of the solution doesn't change when the ammonium nitrate is dissolved in it. Be sure your answer has the correct number of significant digits.

Solution

2NH₄NO₃ + Na₂CrO₄ → (NH₄)₂CrO₄ + 2NaNO₃

We first convert the given parameters to number of moles

Number of moles = (Mass/Molar mass)

Molar mass of NH₄NO₃ = 80.043 g/mol

Number of moles of NH₄NO₃ = (2.59/80.043) = 0.03224 mole

Number of moles = (Concentration in mol/L) × (Volume in L)

Number of moles of Na₂CrO₄ = 0.4 × 0.2 = 0.08 Mole

2 moles of NH₄NO₃ react with 1 mole of Na₂CrO₄

So, it it evident that NH₄NO₃ is the limiting reagent as it is in short supply in the amount needed for the reaction.

So, the number of moles of ammonium ion in the product is also 0.03224 mole.

Molarity = (Number of moles)/(Volume L)

Molarity of ammonium ion = (0.03224/0.2) = 0.1612 mol/L = 0.16 M

Hope this Helps!!!

3 0
2 years ago
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