All categories

3 years ago

Which of the following statements are correct regarding electric field lines and equipotential lines? (Select all that apply.)

Physics

1 answer:

gavmur [86]3 years ago

5 0

Answer:

A)The electric field at a point cannot be in two different directions and therefore two field lines can never cross.

E)If equipotential lines of different potentials cross that would imply that the potential at that point has two different values and that is not physically possible.

Explanation:

A) Field lines cannot be crossed. Otherwise, at the point where the lines cross, there would be two different electric field vectors, which makes no physical sense.

E) Since the electric field is a conservative vector field, it can be defined as the negative value of the gradient of the electric potential, therefore, the same is true as in the previous point.

You might be interested in

How can a heavy moving van have the same momentum as a small motorcycle?

vladimir1956 [14]

Hello there!

The formula for momentum is $p=mv$ .
p is momentum, m is mass, and v is velocity.

The mass of a heavy moving van will be much greater than the mass of a motorcycle, so how can they have the same momentum?

They can have the same momentum if the velocity of the moving van is less than the velocity of the motorcycle, or if the velocity of the motorcycle is greater than the moving van (same thing but differently worded)

Let the mass of the moving van be greater than the mass of the motorcycle by a factor of k. In order for the two to have the same momentum, the velocity of the motorcycle must be greater than the velocity of the moving van by the same factor, k.

Hope this helps! :)

3 0

3 years ago

A 2mC charge traveling 10 m/s nears a wire carrying a 5 A current. If the charge's velocity and the wire's current are perpendic

-BARSIC- [3]

Answer:

The magnetic force on the wire at the moment is 2 micro-Newton/(Ampere-meter)

Explanation:

Formula for magnetic force is F = qvB*sin(theeta)

and B = μ*I / 2*pi*r

where

q = charge in coulomb

v = velocity

B = magnetic field strength

μ = permeability of free space

I = current

so from here we get B = (4*pi*10^(-7))(5) / 2*pi*0.01 = 0.0001-T

now ,

F = (2mC)*(10)*0.0001*sin(90)

F = 2 micro-Newton/(Ampere-meter)

3 0

3 years ago

Dave wishes to get produce from the store, which is a distance D- 2.2 km east of his house. Dave drives his bike to the store at

Neporo4naja [7]

Answer:

a) $t_1=338.4615\ s$

b) $t=1386.0805\ s$

c) $t=23.1013\ min$

d) $d=4400\ m$

e) Since Dave starts from house and finally returns to the house so displacement is zero.

Explanation:

Given:

distance between the house and the store, $s=2.2\ km=2200\ m$

speed of driving from house to store, $v_1=-6.5\ m.s^{-1}$

speed of driving back from store to house, $v_2=2.1\ m.s^{-1}$

Since the store is located towards east from his house and the velocity in this direction is taken negative and contrary to this the velocity in the west direction is taken positive.

time taken in reaching the store:

$t_1=\frac{s}{v_1}$

$t_1=\frac{-2200}{-6.5}$

$t_1=338.4615\ s$

Now the time taken in returning form the store:

$t_2=\frac{s}{v_2}$

$t_2=\frac{2200}{2.1}$

$t_2=1047.6190\ s$

therefore total time taken by the trip:

$t=t_1+t_2$

$t=338.4615+1047.6190$

$t=1386.0805\ s$

the time taken by the trip in minutes:

$t=\frac{1386.0805}{60}$

$t=23.1013\ min$

distance travelled in the whole trip:

$d=2\times s$

$d=2\times 2200$

$d=4400\ m$

Since Dave starts from house and finally returns to the house so displacement is zero.

3 0

3 years ago

Will give correct answer brainliest

Sav [38]

Answer:

.....

Explanation:

i. sorry? i really hope this helps!

4 0

3 years ago

If you ride quickly down a hill on a bicycle your eardrums are pushed in before they pop back. Why is this?

Mice21 [21]

Answer:

<em>The difference in pressure between the external air pressure, and the internal air pressure of the middle ear.</em>

Explanation:

First of all, we should note that pressure decreases with height and increases with depth. The air within the middle ear (between the ear drum and the Eustachian tube) adjusts itself to respond to the atmospheric pressure, or when we yawn. At a high altitude like on the hill, the air pressure in the middle ear, is fairly low (this is to balance the low air pressure at this height). While riding down the hill quickly, there is little time for the air pressure in the ear to readjust itself to the increasing external air pressure, causing the external air to push into the ear drum. Along the way, the air within the middle ear is adjusted by the opening of the Eustachian tube, allowing more air into the space in the middle ear to balance the external air pressure. This readjustment causes the ear to pop.

7 0

3 years ago