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3 years ago

How do compute ratios like this like 1/4miles Sebastian runs in 1.6 minutes. How long did it take him to run one mile

2 answers:

7 0

It's easier to write if you convert 1/4 into 0.25.

$\frac{0.25mi}{1.6min} = \frac{1mi}{xmin}$

Then you use algebra to find that he ran the mile in 6.4 minutes.

jeyben [28]3 years ago

7 0

There are four 1/4 miles in a mile.
4*1.6 = 6.4

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Two bicyclists were racing toward each other when they were 98 miles apart. Three hours later they did not meet yet and the dist

lesya [120]

Let, speed of 1st bicyclist is x.

So, speed of 2nd bicyclist is x-3 .

We know, relative speed when two objects moves towards each other :

$v = x + ( x-3 )\\\\v = 2x - 3$

Now, distance travelled in 3 hours is (98-2) miles .

So,

$2x-3 = \dfrac{96}{3}\\\\2x - 3 = 32\\\\2x = 35\\\\x = 17.5\ mph$

Therefore, speed of bikes are 17.5 mph and 14.5 mph.

Hence, this is the required solution.

5 0

2 years ago

(-31/2)-(-41/4)=-7/2-(17/4)=

Andrew [12]

Just forget about the first half, and just do the second half. It’s way easier. Answer is -7.75

6 0

2 years ago

What expressions represent 5/6 × 5

pickupchik [31]

Answer:

$5 \div 6 \times 5 = 25\div 6$

<h2>25/6 <em>is </em><em>the </em><em>Answer</em></h2>

7 0

2 years ago

Help can someone please help me

kkurt [141]

Answer:

B=55

Step-by-step explanation:

2x+3x+2x+5=180

7x=175

X=25

B= 2x+5

B=2*25 +5

B=55

7 0

3 years ago

Cassie has test grades of 62, 85 and 89 on the first three tests in herpre-algebra class. What are the possible scores she can m

Vsevolod [243]

Explanation:

The test grade for 1st three tests = 62, 85, 89

Let the fourth test score = x

The result we hoping to get is grade B.

Let's find the average of the four test score

$\text{Average = }\frac{Su\text{ m of all test score}}{nu\text{mber of test score}}$ $\begin{gathered} s\text{ um of test scores = 62 + 85 + 89 + x} \\ nu\text{mber of test score = 4} \\ \frac{\text{62 + 85 + 89 + x}}{4}=\text{ Average} \end{gathered}$ $\begin{gathered} A\text{ grade B represents atleast 80} \\ \text{Atleast represents }\ge \\ \frac{\text{62 + 85 + 89 + x}}{4}\text{ }\ge\text{ 80} \\ \frac{\text{236 + x}}{4}\text{ }\ge\text{ 80} \end{gathered}$ $\begin{gathered} \text{236 + x }\ge\text{ }80(4) \\ \text{236 + x }\ge\text{ }320 \\ \text{subtract }236\text{ from both sides:} \\ 236\text{ - 236 + x }\ge\text{ }320\text{ - 23}6 \\ x\text{ }\ge\text{ 84} \end{gathered}$

This means Cassie needs to score 84 or more to get a grade of B

In ineq

3 0

1 year ago