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o-na [289]
3 years ago
11

Heat can never flow from __________.

Physics
1 answer:
IgorLugansk [536]3 years ago
8 0
The correct sentence is:
Heat can never flow from <span>b. cold to hot.

In fact, heat always flows from hot to cold objects. The reason is the following: in an object with higher temperature, the particles move/vibrate faster than the particles in an object with lower temperature. When the two objects are in contact, therefore, the particles of the hotter object have more energy than the particles of the colder object, so the particles of the hotter object transfer more energy to the particles of the colder object, on average. As a result, heat always flows from hot objects to cold objects.</span>
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During wich two time intervals does the particle undergo equal displacement
sweet-ann [11.9K]
Basically, you want to take the integral of each interval and compare them. The two intervals with the same integral represent equal displacement of the particle. And since delta(x) is always 2, all you have to do is average the initial and final velocities of each interval and multiply by two to find total displacement.

Hope it helped.

Edit to show calculations:

2 * [ (0 + 10)/2 ] = 10 for interval AB
2 * [ (7 + 3)/2 ] = 10 for interval DE
8 0
3 years ago
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 2.4
NeX [460]

When person is observing destructive interference at 0.20 m distance from the equidistant position then we can say that path difference must be equal to half of the wavelength

now we will have

\frac{\lambda}{2} = \frac{yd}{L}

now we know that

y = 0.20 m

d = 2.4 m

L = 10 m

now here we have

\frac{\lambda}{2} = \frac{0.20\times 2.4}{10}

\lambda = 0.096 m

now frequency of wave is given as

f = \frac{v}{\lambda}

f = \frac{343}{0.096} = 3573 Hz

5 0
3 years ago
Microwave transmission involves sending signals from one microwave station to another. What is this often called?
astraxan [27]
It is called fixed wireless

4 0
3 years ago
A ball is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. The ball rises to a height equa
alukav5142 [94]

Answer:

d. equal to one-fourth the acceleration at the surface of the asteroid.

Explanation:

The explanation is attached as a picture with this answer

Newton's law of universal gravitation is being used to compare the accelerations at the surface and at the top of the ball's path.

as it can be seen in the explanation that the proportional form of the equation is used because we do not need to necessarily use to final form with "G" for comparison calculations.

As per the given scenario only difference between the two points in the gravitational field is the distance from center of the spherical asteroid, i.e. r.

It is  taken 2r for the top is the path. hence we obtain (1/4)g as our answer.

4 0
4 years ago
Read 2 more answers
Can someone help me with this please?
Slav-nsk [51]

Answer:

C2, C1, C4, C5 and C6 are in parallel. Therefore, we use the formula Cp = C1 + C2 + ....

Cp = C2 + C1 + C4 + C5 + C6 = ( 7 * 10 ^-3) + (18 * 10^-6) + (0.8F) + (200 * 10^-3 F) + (750 * 10^-6) = 1.008F

Now, Cp will become one capacitor and it will be aligned with C3, therefore it will now become a circuit in series.

We use the formula: 1/Cs = 1/C1 + 1/C2 + .... + ....1/Cn

Thus,

1/Cs = 1/C3 + 1/Cp

1/Cs = 1/(14 * 10^-3 F) + 1/(1.008F)

Cs = 1.4 * 10 ^-2 or if we do not round too much it will give exactly 0.0138 F

So the answer should be a)

8 0
3 years ago
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