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strojnjashka [21]
3 years ago
14

As a tennis ball is struck, it departs from the racket horizontally with a speed of 28.0 m/s. The ball hits the court at a horiz

ontal distance of 19.6 m from the racket. How far above the court is the tennis ball when it leaves the racket?
Physics
1 answer:
amid [387]3 years ago
7 0

solution:

long to travel 19.6m at 28m/s

t =19.6/28

=time taken to drop from rest

s=ut+(1/2)at^2

u=0

a=~10

so s=(1/2)*10*(19.6/28)^2 =2.45m

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Photograph E shows a rechargeable torch. When a student shakes the torch, the magnet moves through the coil and back again. This
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a) according to Faraday's law , b) creating a faster movement, placing more turns on coil

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Cheetahs the worlds fastest land animals can run up to about 125km/h. a cheetah chasing an impala runs 32m [N], then suddenly tu
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(10%) Problem 5: The Earth spins on its axis and also orbits around the Sun. For this problem use the following constants. Mass
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Incomplete Question.The Complete question is

The Earth spins on its axis and also orbits around the Sun. For this problem use the following constants.  Mass of the Earth: 5.97 × 10^24  kg (assume a uniform mass distribution)  Radius of the Earth: 6371 km  Distance of Earth from Sun: 149,600,000 km

(i)Calculate the rotational kinetic energy of the Earth due to rotation about its axis, in joules.

(ii)What is the rotational kinetic energy of the Earth due to its orbit around the Sun, in joules?  

Answer:

(i) KE= 2.56e29 J

(ii) KE= 2.65e33 J

Explanation:

i) Treating the Earth as a solid sphere, its moment of inertia about its axis is

I = (2/5)mr² = (2/5) * 5.97e24kg * (6.371e6m)²

I = 9.69e37 kg·m²

About its axis,

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ω= 7.27e-5 rad/s,

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KE= 2.56e29 J

(ii) About the sun,

I = mR²

I= 5.97e24kg * (1.496e11m)²

I= 1.336e47 kg·m²

and the angular velocity

ω = 2π rad/yr * 1yr/365.25day * 1day/24h * 1h/3600s

ω= 1.99e-7 rad/s

so  

KE = ½ * 1.336e47kg·m² * (1.99e-7rad/s)²

KE= 2.65e33 J

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3 years ago
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