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Vladimir79 [104]
3 years ago
9

When a hacking technique uses persuasion and deception to get a person to provide information to help compromise security, this

is referred to as what?
Engineering
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

Social engineering

Explanation:

Social engineering in terms of information security has to do with using manipulative tricks to get confidential statements or information from people in order to perpetrate crimes, such information includes bank details, password, etc. Social engineering is adopted by criminals because it is easier to use natural inclination make people trust you and divulge confidential information to you than make moves to either hack or break cyber security.

Yanka [14]3 years ago
4 0
<h2>Answer:</h2>

Social engineering

<h2>Explanation:</h2>

Social engineering is one of the hacking techniques available. In social engineering, an unsuspecting user is lured, persuaded or convinced by cyber criminals to provide certain confidential data and information (such as passwords, credit card pin e.t.c) which can then be used to compromise security either by infecting the user's system with malware or deceptively making them to visit certain infected sites.

Examples of social engineering hacking techniques, among others, are;

i. Baiting

ii. Phishing

iii. Vishing

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In the truss below, the vertical reaction force at A is
Montano1993 [528]
It’s c trust just trust
7 0
3 years ago
The Environmental Protection Agency (EPA) has standards and regulations that says that the lead level in soil cannot exceed the
DENIUS [597]

Answer:

See below

Explanation:

<u>Check One-Sample T-Interval Conditions</u>

Random Sample? √

Sample Size ≥30? √

Independent? √

Population Standard Deviation Unknown? √

<u>One-Sample T-Interval Information</u>

  • Formula --> CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})
  • Sample Mean --> \bar{x}=390.25
  • Critical Value --> t^*=2.0096 (given df=n-1=50-1=49 degrees of freedom at a 95% confidence level)
  • Sample Size --> n=50
  • Sample Standard Deviation --> S_x=30.5

<u>Problem 1</u>

The critical t-value, as mentioned previously, would be t^*=2.0096, making the 95% confidence interval equal to CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})=390.25\pm2.0096(\frac{30.5}{\sqrt{50}})\approx\{381.5819,398.9181\}

This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.

3 0
2 years ago
If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ p ^ is approximately a normal distribution.
defon

Answer:

It is true that the sampling distribution of the proportions is approximately a normal distribution.

Explanation:

Solution

Given that:

N = 50

P= 0.8

Thus

p ^ =√p(1-p)/n

p ^=√0.8 (1-0.8)/50

p ^= 0.0566

Therefore,we conclude that the sampling distribution of the proportions is approximately a normal distribution.

4 0
3 years ago
Print "userNum1 is negative." if userNum1 is less than 0. End with newline. Assign userNum2 with 2 if userNum2 is greater than 1
miv72 [106K]

Answer:

From the question, we have two variables

1. userNum1

2. userNum2

And we are to print "userNum1 is negative" if userNum1 is less than 0.

Then Assign userNum2 with 2 if userNum2 is greater than 10.

Otherwise, print "userNum2 is less or equal 10.".

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main ()

{

// Declare variables

int userNum1, userNum2;

// Accept input for these variables

cin>>userNum1, userNum2;

// Condition 1

if(userNum1 < 0)

{

cout<<"userNum1 is negative"<<'\n';

}

// Condition 2

if(userNum2 > 10)

{

userNum2 = 2;

}

// If condition is less than 10

else

{

cout<<"userNum2 is less or equal to 10"<<\n;

}

return 0;

}

// End of Program.

3 0
3 years ago
Stainless steel ball bearings (rho = 8085 kg/m3 and cp = 0.480 kJ/kg·°C) having a diameter of 1.2 cm are to be quenched in water
sveticcg [70]

Answer:

\dot Q = -2.341\,kJ

Explanation:

The rate of heat transfer from the balls to the air is:

\dot Q = \left[(800\,\frac{1}{min} )\cdot (\frac{1\,min}{60\,s} )\cdot(8085\,\frac{kg}{m^{3}})\cdot (\frac{4}{3}\pi )\cdot (6\times 10^{-3}\,m)^{3}\right]\cdot (0.480\,\frac{kJ}{kg\cdot ^{\textdegree}C} )\cdot (850\,^{\textdegree}C-900\,^{\textdegree}C)\dot Q = -2.341\,kJ

3 0
4 years ago
Read 2 more answers
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