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Vladimir79 [104]
3 years ago
9

When a hacking technique uses persuasion and deception to get a person to provide information to help compromise security, this

is referred to as what?
Engineering
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

Social engineering

Explanation:

Social engineering in terms of information security has to do with using manipulative tricks to get confidential statements or information from people in order to perpetrate crimes, such information includes bank details, password, etc. Social engineering is adopted by criminals because it is easier to use natural inclination make people trust you and divulge confidential information to you than make moves to either hack or break cyber security.

Yanka [14]3 years ago
4 0
<h2>Answer:</h2>

Social engineering

<h2>Explanation:</h2>

Social engineering is one of the hacking techniques available. In social engineering, an unsuspecting user is lured, persuaded or convinced by cyber criminals to provide certain confidential data and information (such as passwords, credit card pin e.t.c) which can then be used to compromise security either by infecting the user's system with malware or deceptively making them to visit certain infected sites.

Examples of social engineering hacking techniques, among others, are;

i. Baiting

ii. Phishing

iii. Vishing

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harina [27]

Answer:

C

Explanation:

I just did the test on enginuity and it also is the only one that makes sence

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3 years ago
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Within a cubic unit cell, sketch the directions of [012], [721], [110].
exis [7]

Answer:

[012]  :

Here x component is zero. That is why this is  in y- z plane

[721] :      

This is  in  all three plane .It means it is in space.

[110]  :

Here z component is zero.

That is why this is  in x -y plane

From the cubic unit directions we can easily understand all given directions  [012], [721], [110].

7 0
3 years ago
The equation for the velocity V in a pipe with diameter d and length L, under laminar condition is given by the equation V=Δpdsq
Citrus2011 [14]

Answer:

Given that

V=\dfrac{\Delta Pd^2}{32\mu L}

LHS of above given equation have dimension [M^oL^{1}T^{-1}].

Now find the dimension of RHS

Dimension of P = [ML^{-1}T^{-2}].

Dimension of d=  [M^{0}L^{1}T^{0}].

Dimension of μ =  [ML^{-1}T^{-1}].

Dimension of L=  [M^{0}L^{1}T^{0}].

So

\dfrac{\Delta Pd^2}{32\mu L}=\dfrac{[ML^{-1}T^{-2}].[M^{0}L^{1}T^{0}]^2}{[ML^{-1}T^{-1}].[M^{0}L^{1}T^{0}]}

\dfrac{\Delta Pd^2}{32\mu L}=[M^0L^{1}T^{-1}]

It means that both sides have same dimensions.

5 0
4 years ago
Suppose you want to buy a new car. The car will be used mainly for going to work, shopping, running errands, and visiting friend
Sergeu [11.5K]
1. So you can complete the things you NEED to do faster. (I.e work, groceries)

2. So it’s easier for you to do leisure activities. (I.e visiting friends, shopping)
5 0
3 years ago
The volume of 1.5 kg of helium in a frictionless piston-cylinder device is initially 6 m3. Now, helium is compressed to 2 m3 whi
coldgirl [10]

Answer:

The initial temperature will be "385.1°K" as well as final will be "128.3°K".

Explanation:

The given values are:

Helium's initial volume, v₁ = 6 m³

Mass, m = 1.5 kg

Final volume, v₂ = 2 m³

Pressure, P = 200 kPa

As we know,

Work, W=p(v_{2}-v_{1})

On putting the estimated values, we get

⇒            =200000(2-6)

⇒            =200000\times (-4)

⇒            =800,000 \ N.m

Now,

Gas ideal equation will be:

⇒  pv_{1}=mRT_{1}

On putting the values. we get

⇒  200000\times 6=1.5\times 2077\times T_{1}

⇒  T_{1}=\frac{1200000}{3115.5}

⇒       =385.1^{\circ}K (Initial temperature of helium)

and,

⇒  pv_{2}=mRT_{2}

On putting the values, we get

⇒  200000\times 2=1.5\times 2077\times T_{2}

⇒  T_{2}=\frac{400000}{3115.5}

⇒       =128.3^{\circ}K (Final temperature of helium)

3 0
3 years ago
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