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ki77a [65]
3 years ago
14

Who engineered the first satalite on the moon before the bible was created​

Engineering
1 answer:
Ganezh [65]3 years ago
6 0

Explanation:

Apollo 8 Genesis reading

On Christmas Eve, December 24, 1968, the crew of Apollo 8 read from the Book of Genesis as they orbited the Moon. Astronauts Bill Anders, Jim Lovell, and Frank Borman, the first humans to travel to the Moon, recited verses 1 through 10 of the Genesis creation narrative from the King James Bible.[1] Anders read verses 1–4, Lovell verses 5–8, and Borman read verses 9 and 10.

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Write a Pig script and run it in local mode on this data to find out the top 10 states according to the land area. Since you wan
ELEN [110]

Explanation:

Apache Pig script execution modes

Local mode: In 'local mode', you can run the pig script on the local file system. In this case, you don't need to store the data in the Hadoop HDFS file system, instead you can work with the data stored in the local file system.

MapReduce mode: In 'MapReduce mode', the data must be stored in the HDFS file system and you can process the data with the help of pig script.

Apache Pig Script in MapReduce mode

Let's say our task is to read data from a data file and display the required contents in the terminal as output.

The sample data file contains the following data:

Txt information file - Apache Pig Script - Edureka

Save the text file with the name 'information.txt'

The sample data file contains five First Name, Last Name, Mobile Number, City, and Profession columns separated by the tab key. Our task is to read the contents of this HDFS file and display all the columns of these records.

To process this data using Pig, this file must be present in Apache Hadoop HDFS.

Command: hadoop fs –copyFromLocal /home/edureka/information.txt / edureka

3 0
3 years ago
Given the complex numbers A1 5 6/30 and A2 5 4 1 j5, (a) convert A1 to rectangular form; (b) convert A2 to polar and exponential
Deffense [45]

This question is incomplete, the complete question is;

Given the complex numbers A₁ = 6∠30 and A₂ = 4 + j5;

(a) convert A₁ to rectangular form

(b) convert A₂ to polar and exponential form

(c) calculate A₃ = (A₁ + A₂), giving your answer in polar form

(d) calculate A₄ = A₁A₂, giving your answer in rectangular form

(e) calculate A₅ = A₁/(A^{*}₂), giving your answer in exponential form.

Answer:

a) A₁ in rectangular form is 5.196 + j3

b) value of A₃  in polar form is 12.19∠41.02°

The polar form of A₂ is 6.403 ∠51.34°, exponential form of A₂ = 6.403e^{j51.34 }

c) value of A₃  in polar form is 12.19∠41.02°

d) A₄ in rectangular form is 5.784 + j37.98

e) A₅ in exponential form is 0.937e^{j81.34 }

Explanation:

Given data in the question;

a) A₁ = 6∠30

we convert A₁ to rectangular form

so

A₁ = 6(cos30° + jsin30°)

= 6cos30° + j6cos30°

= (6 × 0.866) + ( j × 6 × 0.5)

A₁  =  5.196 + j3

Therefore, A₁ in rectangular form is 5.196 + j3

b) A₂ = 4 + j5

we convert to polar and exponential form;

first we convert to polar form

A₂ = √((4)² + (5)²) ∠tan⁻¹( \frac{5}{4} )

= √(16 + 25) ∠tan⁻¹( 1.25 )

= √41 ∠ 51.34°

A₂ = 6.403 ∠51.34°

The polar form of A₂ is 6.403 ∠51.34°

next we convert to exponential form;

A∠β can be written as Ae^{j\beta }

so, A₂  in exponential form will be;

A₂ = 6.403e^{j51.34 }

exponential form of A₂ = 6.403e^{j51.34 }

c) A₃ = (A₁ + A₂)

giving your answer in polar form

so, A₁ = 6∠30 = 5.196 + j3 and A₂ = 4 + j5

we substitute

A₃ = (5.196 + j3) + ( 4 + j5)

= 9.196 + J8

next we convert to polar

A₃ = √((9.196)² + (8)²) ∠tan⁻¹( \frac{8 }{9.196} )

A₃ = √(84.566416 + 64) ∠tan⁻¹( 0.8699)

A₃ = √148.566416 ∠41.02°    

A₃ = 12.19∠41.02°

Therefore, value of A₃  in polar form is 12.19∠41.02°

d) A₄ = A₁A₂

giving your answer in rectangular form

we substitute

A₄ = (5.196 + j3) ( 4 + j5)

= 5.196( 4 + j5) + j3( 4 + j5)

= 20.784 + j25.98 + j12 - 15

A₄ = 5.784 + j37.98

Therefore, A₄ in rectangular form is 5.784 + j37.98

e) A₅ = A₁/(A^{*}₂)

giving your answer in exponential form

we know that A^{*}₂ is the complex  conjugate of A₂

so

A^{*}₂ = (6.403 ∠51.34° )*

= 6.403 ∠-51.34°

we convert to exponential form

A∠β can be written as Ae^{j\beta }

A^{*}₂  = 6.403e^{-j51.34 }

also

A₁ = 6∠30

we convert to polar form

A₁ = 6e^{j30 }

so A₅ = A₁/(A^{*}₂)

A₅ = 6e^{j30 } / 6.403e^{-j51.34 }

A₅  = (6/6.403) e^{j(30+51.34) }

A₅  = 0.937e^{j81.34 }

Therefore A₅ in exponential form is 0.937e^{j81.34 }

6 0
3 years ago
Can anyone tell me what rock this is?
Oksi-84 [34.3K]

Answer: answer is B

Explanation:

8 0
3 years ago
Read 2 more answers
24) A technician is load testing a fully charged battery rated at 600 cold-cranking amps (CCA). The ambient temperature is 70 F
Anvisha [2.4K]

The current draw that should be used for the test by the technician when charging the battery is C. 600 amps for 30seconds.

<h3>Who is a technician?</h3>

It should be noted that a technician simply means an individual that is in charge of a technical equipment.

In this case, since the technician is load testing a fully charged battery rated at 600 cold-cranking amps, the current draw that should be used is 600 amps for 30seconds.

Learn more about technicians on:

brainly.com/question/5122191

#SPJ1

7 0
2 years ago
Briefly explain why someone would choose a career in the geologic sciences, with at least three reasons.
Artemon [7]

Answer:

Someone could chose the career of being a geologic scientist because they can discover new things about the world.And find new things about it that wearnt discovered previously.

Explanation:

New species

New cures

New lands

3 0
3 years ago
Read 2 more answers
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