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Shkiper50 [21]
3 years ago
11

Convert 771.8 g to kg

Chemistry
1 answer:
Molodets [167]3 years ago
8 0
The amount of kilograms is 0.7718
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How many grams of CO2 are produced from 51 g of CH4
Elina [12.6K]

Answer:

use the equation Mass= RFM*Moles

Explanation:

use your periodic table

and create a little table

3 0
3 years ago
You have 350 mL of 3.4 M hydrochloric acid (HCl). How many grams of HCl gas are dissolved? Bonus: what is the volume of the HCl
Crank

Answer:

1. 43.44g of HCl

2. 26.67 L of HCl

Explanation:

1) Molarity of a solution = number of moles (n) ÷ Volume (V)

According to the provided information in this question,

V = 350 mL = 350/1000 = 0.350L

Molarity = 3.4 M

Using Molarity = n/V

3.4 = n/0.350

n = 3.4 × 0.350

n = 1.19mol

Using the formula below to calculate the mass of HCl;

mole = mass/molar mass

Molar mass of HCl = 1 + 35.5 = 36.5g/mol

mole = mass/MM

mass = 1.19 mol × 36.5g/mol

mass = 43.44g of HCl

2) At STP, HCl has a pressure of 1atm, a temperature of 273K

V = ?

n = 1.19 mol

R = 0.0821 Latm/molK

Using PV = nRT

V = nRT/P

V = 1.19 × 0.0821 × 273/1

Volume = 26.67L

5 0
3 years ago
Iron sulfite has the formula?
Mademuasel [1]
Its FeSO3 or iron(iii)sulfite = Fe2(SO3)3
7 0
3 years ago
Noble gas configuration
saw5 [17]

Answer:

Rubidium= [Kr] 5s^1

Calcium= [Ar] 4s^2

Aluminium= [Ne] 3s^2 3p^1

Explanation:

A noble gas configuration begins with the elemental symbol of the last noble gas prior to the atom. The symbol is then followed by the remaining electrons.

Hope this helped! good luck :)

3 0
3 years ago
An aluminum kettle weights 1.05 kg and has a heat capacity of 0.9211 J over grams Celsius how much heat is required to increase
Serggg [28]

Answer:

64799.4 J

Explanation:

The following data were obtained from the question:

Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g

Specific heat capacity (C) = 0.9211 J/g°C

Initial temperature (T1) = 23°C

Final temperature (T2) = 90°C

Change in temperature (ΔT) = T2 – T1 =

90°C – 23°C = 67°C

Heat required (Q) =....?

The heat required to increase the temperature of the kettle can b obtain as follow:

Q = MCΔT

Q = 1050 x 0.9211 x 67

Q = 64799.4 J

Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.

4 0
3 years ago
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