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Nadusha1986 [10]
3 years ago
13

The heat of vaporization for ethanol is 0.826 kJ/j. Calculate the heat energy in joules required to boil 45.65g of ethanol

Chemistry
2 answers:
andrey2020 [161]3 years ago
6 0

Answer:

ethanol is already at the ethanol's boiling point: (0.826 kJ/g) x (70.05 g) = 57.8613 kJ = 5.79 x 10^4 J.

Missing: 45.65 ‎| ‎Must include: ‎45.65

Explanation:

Rashid [163]3 years ago
5 0

Answer:

Explanation:

Supposing the temperature of the ethanol is already at the ethanol's boiling point:

(0.826 kJ/g) x (70.05 g) = 57.8613 kJ = 5.79 x 10^4 J

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Two examples of energy transformations are shown.
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3 years ago
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3 years ago
How many grams of CaCl2 are needed to make 277.8g of a solution that is 31.5% (m/m) in water? Note that mass is not technically
Sveta_85 [38]

<u>Answer:</u> The mass of calcium chloride present in given amount of solution is 87.5 g

<u>Explanation:</u>

We are given:

Mass of solution = 277.8 grams

Also, 31.5 % (m/m) of calcium chloride in water. This means that 31.5 g of calcium chloride is present in 100 g of solution.

To calculate the mass of calcium chloride in the given amount of solution, we use unitary method:

in 100 g of solution, the mass of calcium chloride present is 31.5 g

So, 277.8 g of solution, the mass of calcium chloride present is \frac{31.5}{100}\times 277.8=87.5g

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8 0
3 years ago
A sample of gas at a pressure of 121.59 kPa, a volume of 31 L, and a temperature of 360 K contains how many moles of gas? A. 0.7
natali 33 [55]

Answer:

C. 1.3 mol

Explanation:

PV = nRT

where P is absolute pressure,

V is volume,

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and T is absolute temperature.

Given:

P = 121.59 kPa

V = 31 L

T = 360 K

R = 8.3145 L kPa / mol / K

Find: n

n = PV / (RT)

n = (121.59 kPa × 31 L) / (8.3145 L kPa / mol / K × 360 K)

n = (3769.29 L kPa) / (2993.22 L kPa / mol)

n = 1.26 mol

Round to two significant figures, there are 1.3 moles of gas.

4 0
3 years ago
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