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Nadusha1986 [10]
3 years ago
13

The heat of vaporization for ethanol is 0.826 kJ/j. Calculate the heat energy in joules required to boil 45.65g of ethanol

Chemistry
2 answers:
andrey2020 [161]3 years ago
6 0

Answer:

ethanol is already at the ethanol's boiling point: (0.826 kJ/g) x (70.05 g) = 57.8613 kJ = 5.79 x 10^4 J.

Missing: 45.65 ‎| ‎Must include: ‎45.65

Explanation:

Rashid [163]3 years ago
5 0

Answer:

Explanation:

Supposing the temperature of the ethanol is already at the ethanol's boiling point:

(0.826 kJ/g) x (70.05 g) = 57.8613 kJ = 5.79 x 10^4 J

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DanielleElmas [232]

The pH at equivalence point is 12.46

At equivalence point, number of moles of acid, n equals number of moles of base, n'

So, n = n'

CV = C'V' where

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We know that the ion-product of water Kw is

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Since pH = -㏒[H⁺]

pH = -㏒[3.495 × 10⁻¹³]

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Learn more about pH at equivalence point here:

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