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tatuchka [14]
3 years ago
6

A car traveling at a speed of 30.0 m/s encounters an emergency and comes to a complete stop in 7.5 seconds? What is the cars acc

eleration?
Chemistry
1 answer:
Marianna [84]3 years ago
6 0

Answer:

The acceleration is: 4m/s^2

Explanation:

Given

u = 30.0m/s --- The initial velocity

t = 7.5s --- time

v = 0m/s -- The final velocity

Required

Determine the acceleration

To do this, we make use of the first equation of motion

v = u - at

We used negative because the car was coming to stop.

This gives:

0 = 30 - 7.5 * a

0 = 30 - 7.5a

Collect like terms

7.5a = 30

Solve for a

a = \frac{30}{7.5}

a = 4m/s^2

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A species of rabbit lives in a grassland ecosystem. Rabbits of this species have brown fur that allows them to blend in with the
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Explanation:

The fur of the rabbit species changes over time from brown to white which helps them to blend with the environment.

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3 years ago
125 cm3 of a solution contains 0.25 moles of the solute. What is the concentration of the solution?
jarptica [38.1K]

Answer:

Explanation:

125 cm3 -> 0.125 L

M = no. mole / volume (L)

M = 0.25 / 0.125 = 2 M

3 0
3 years ago
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tino4ka555 [31]

Answer:

The answer is 375.54 g of AgBr

Explanation:

Mass (g) = Concentration (mol/L) x volume (L) x Molecular Weight of AgBr (g/mol)

Mass = 2M x 1L x 187.77 g/mol

Mass = 375.54g

6 0
2 years ago
Magnesium metal burns in air to form a mixture of magnesium oxide (MgO, M = 40.31) and magnesium nitride (Mg3N2, M = 100.95). A
dedylja [7]

Answer:

26.95 %

Explanation:

Air contains the highest percentage of oxygen and nitrogen gases. Magnesium then combines with both of the gases:

2 Mg (s) + O_2 (g)\rightarrow 2 MgO (s)

3 Mg (s) + N_2 (g)\rightarrow Mg_3N_2 (s)

Firstly, find the total number of moles of magnesium metal:

n_{Mg} = \frac{1.000 g}{24.305 g/mol} = 0.041144 mol

Let's say that x mol react in the first reaction and y mol react in the second reaction. This means:

x + y = 0.041144 mol

According to stoichiometry, we form:

n_{MgO} = x mol, n_{Mg_3N_2} = \frac{y}{3} mol

Multiplying moles by the molar mass of each substance will yield mass. This means we form a total of:

m_{MgO} = 40.31x g, m_{Mg_3N_2} = \frac{y}{3} 100.95 g =

The total mass is given, so we have our second equation to solve:

40.31x + 33.65y = 1.584

We have two unknowns and two equations, we may then solve:

x + y = 0.041144

40.31x + 33.65y = 1.584

Express y from the first equation:

y = 0.041144 - x

Substitute into the second equation:

40.31x + 33.65(0.04144 - x) = 1.584

40.31x + 1.39446 - 33.65x = 1.584

6.66x = 0.18954

x = 0.028459

y = 0.041144 - x = 0.012685

Moles of nitride formed:

n_{Mg_3N_2} = \frac{y}{3} = 0.0042282 mol

Convert this to mass:

m_{Mg_3N_2} = 0.0042282 mol\cdot 100.95 g/mol = 0.4268 g

Find the percentage:

\omega_{Mg_3N_2} = \frac{0.4268 g}{1.584 g}\cdot 100\% = 26.95 \%

7 0
3 years ago
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